What is the value of F_max for an impulse of 6.8 Ns in the given figure?

  • Thread starter Thread starter krej
  • Start date Start date
  • Tags Tags
    Impulse
Click For Summary
SUMMARY

The value of F_max required to achieve an impulse of 6.8 Ns, as derived from the discussion, is 1700 N. The impulse is calculated using the relationship between force and time, specifically considering the area under the force-time graph. The correct approach involves recognizing that the time axis is in milliseconds, which affects the calculation of F_max. The initial attempts using constant force and triangular area calculations were incorrect due to this oversight.

PREREQUISITES
  • Understanding of impulse and its relation to force and time
  • Knowledge of integral calculus as it applies to force-time graphs
  • Familiarity with units of measurement, specifically converting milliseconds to seconds
  • Ability to calculate the area under a curve, particularly for triangular shapes
NEXT STEPS
  • Review the concept of impulse in physics and its mathematical formulation
  • Study the relationship between force, time, and impulse using real-world examples
  • Learn about the implications of unit conversions in physics calculations
  • Explore graphical methods for calculating impulse from force-time graphs
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and impulse, as well as educators looking for examples of force-time relationships in problem-solving contexts.

krej
Messages
12
Reaction score
0

Homework Statement


In the figure , what value of F_max gives an impulse of 6.8 Ns?
http://img76.imageshack.us/img76/1782/09ex05.jpg

Homework Equations


Integral of F with respect to time equals impulse


The Attempt at a Solution


I tried doing two things, and they were both wrong.

First, i tried the integral of F with respect to time from 0 to 8 = 6.8.
Ft from 0 to 8 = 6.8
F(8) - F(0) = 6.8
F = 6.8/8
F = 0.85
I realize that is wrong though, since the picture they give us isn't of constant force.

So then I tried using the area of a triangle:
Area = (1/2)b*h
Area = (1/2)*8*h
4h = 6.8
h = 6.8/4 = 1.7

So I entered 1.7 into the website, and it said it was wrong. If that didn't work, I have no idea what else I could do to find it.
 
Last edited by a moderator:
Physics news on Phys.org
krej said:

Homework Statement


In the figure , what value of F_max gives an impulse of 6.8 Ns?
http://img76.imageshack.us/img76/1782/09ex05.jpg

Homework Equations


Integral of F with respect to time equals impulse


The Attempt at a Solution


I tried doing two things, and they were both wrong.

First, i tried the integral of F with respect to time from 0 to 8 = 6.8.
Ft from 0 to 8 = 6.8
F(8) - F(0) = 6.8
F = 6.8/8
F = 0.85
I realize that is wrong though, since the picture they give us isn't of constant force.

So then I tried using the area of a triangle:
Area = (1/2)b*h
Area = (1/2)*8*h
4h = 6.8
h = 6.8/4 = 1.7

So I entered 1.7 into the website, and it said it was wrong. If that didn't work, I have no idea what else I could do to find it.
Note that the units on the time axis are miliseconds. Hence, 4x10^-3*Fmax==6.8, Fmax==1700N.
 
Last edited by a moderator:
Oh, wow I didn't notice that at all. I'm too used to it always being in seconds I didn't even think about looking at that. :p

Thanks a lot for your help!
 

Similar threads

Replies
7
Views
2K
Replies
4
Views
2K
  • · Replies 13 ·
Replies
13
Views
9K
  • · Replies 24 ·
Replies
24
Views
4K
  • · Replies 3 ·
Replies
3
Views
5K
Replies
2
Views
972
  • · Replies 2 ·
Replies
2
Views
14K
Replies
7
Views
2K
  • · Replies 21 ·
Replies
21
Views
13K
Replies
9
Views
2K