What is the value of k for the decreasing volume of chlorine in a swimming pool?

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The volume of chlorine, C litres, in a swimming pool decreases over time and is modeled by the equation C(t) = C0e^(kt), where C0 is the initial volume. In this case, C0 is 3 litres, and after 8 hours, the volume is 2.5 litres. To find the value of k, the equation C(8) = 3e^(8k) = 2.5 can be used. Solving this equation yields the exact value of k, which represents the rate of decrease of chlorine in the pool.

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13 The volume of chlorine, C litres, in a swimming pool at time t hours after it was placed in
the pool can be modeled by C(t) = C0e^kt, t ≥ 0. The volume of chlorine in the pool is
decreasing. Initially the volume of chlorine in the pool was 3 litres, 8 hours later the
volume was 2.5 litres.

b Find the exact value of k.
i tried to work this question out but it do not turned out to be right.
i used C(t)=3e^kt
where c(t)=3
then there is another equation C(t)=2.5e^8t
then i used simultanoeus equation
is this method correct?



thank you
 
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rachael said:
13 The volume of chlorine, C litres, in a swimming pool at time t hours after it was placed in
the pool can be modeled by C(t) = C0e^kt, t ≥ 0. The volume of chlorine in the pool is
decreasing. Initially the volume of chlorine in the pool was 3 litres,
This means C(0) = 3. Plug it in the expression for C(t), we have:
C(t) = C(0)ekt = 3ekt, right?
8 hours later the
volume was 2.5 litres.
This means that C(8) = 3ek8 = 2.5
From here, can you solve for k?
By the way, this can be done exactly in the same way as this problem.
Can you go from here? :)
 
thank you
...
 

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