What is the value of n for the level in which the electron originated?

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SUMMARY

The discussion centers on calculating the principal quantum number (n) for an electron in a hydrogen atom that relaxes to the n=4 level and emits light at a frequency of 114 THz. The calculations confirm that the electron originated from the n=6 level, using the formula E=hf, where E is energy, h is Planck's constant (6.63 x 10^-34), and f is frequency. The energy difference (delta E) is derived from the energy levels of the hydrogen atom, leading to the conclusion that n=6 is the correct value.

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  • Study the derivation of energy levels in hydrogen atoms using the formula En = -13.6/n^2
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An electron in a hydrogen atom relaxes to the n= 4 level, emitting light of 114THz.
 
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should be n=6
E=hf = (6.63*10^-34)(114*10^12) = 7.56*10^-20J = 0.472eV
E4= -13.6/4^2
En = -13.6/n^2
delta E =En-E4=0.85-13.6/n^2
deltaE = 0.472
you will find n=6
 
Thank you so much, but i have one question:

when u did 114*10^12 was that showing the conversion factor from THz to Hz?
 
also in the first step, how did u convert from J to eV? And where did delta E come from?
 
1THz = 10^12 Hz
1eV =1.6*10^-19 J
(7,.56 *10^-20)/(1.6*10^-19) = ? eV
 

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