An electron in a hydrogen atom relaxes to the n= 4 level, emitting light of 114THz.
should be n=6
E=hf = (6.63*10^-34)(114*10^12) = 7.56*10^-20J = 0.472eV
En = -13.6/n^2
delta E =En-E4=0.85-13.6/n^2
deltaE = 0.472
you will find n=6
Thank you so much, but i have one question:
when u did 114*10^12 was that showing the conversion factor from THz to Hz?
also in the first step, how did u convert from J to eV? And where did delta E come from?
1THz = 10^12 Hz
1eV =1.6*10^-19 J
(7,.56 *10^-20)/(1.6*10^-19) = ? eV
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