What is the vector perpendicular to the surface given by z = Ax + By + C?

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SUMMARY

The discussion focuses on calculating the flux of the vector field F = through the surface defined by the equation z = Ax + By + C. The key formula for flux involves the dot product of the vector field F and the normal vector n, which is determined to be for the given surface. The method to derive the normal vector from the surface equation is clarified, emphasizing that for a surface defined by f(x,y,z) = constant, the normal vector is given by the gradient ∇f.

PREREQUISITES
  • Understanding of vector fields and flux integrals
  • Knowledge of surface equations in three-dimensional space
  • Familiarity with the gradient operator ∇
  • Basic proficiency in double integrals
NEXT STEPS
  • Study the calculation of flux integrals in vector calculus
  • Learn about the gradient and its applications in determining normal vectors
  • Explore examples of flux through various surfaces
  • Investigate the implications of the Divergence Theorem in relation to flux
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Students and professionals in mathematics, physics, and engineering who are working with vector calculus, particularly those interested in surface integrals and flux calculations.

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[Q] Find the integral that represents the flux of the vector F = <x^2z, x^z, x^2z> through the surface S given by z = Ax + By + C for 0 <= x <= a and 0 <= y <= a, where A, B, C, and a are positive constants.

From what I remember of the Flux.

F dot n, where n is a a vector perpendicular to the plane.
double integral F dot (ru cross rv) du dv

What I'm not remembering is how I get the n.
 
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A vector perpendicular to a plane, given by Ax+ By+ Cz= D is <A, B, C>. Of course, your z= Ax+ By+ C is the same as Ax+ By- z= -C which has normal vector <A, B, -1>.

More generally, if you are given a surface by f(x,y,z)= constant, the vector perpendicular to that surface is \nabla f.
 

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