What is the Velocity of the Second Ship Relative to the First Ship?

Click For Summary
SUMMARY

The discussion focuses on calculating the velocity of the second ship relative to the first ship, with the first ship moving at 25 mi/h at 15 degrees west of north and the second ship at 20 mi/h at 25 degrees south of west. The key equations used are V1 + r = V2 and V2 - V1 = r, where r represents the relative velocity. Participants confirm the approach of breaking down the velocities into components and using the Pythagorean theorem to find the magnitude and direction using tan-1(y/x).

PREREQUISITES
  • Understanding of vector addition and subtraction
  • Knowledge of trigonometric functions, specifically sine and cosine
  • Familiarity with the Pythagorean theorem
  • Basic understanding of angular measurements in navigation
NEXT STEPS
  • Study vector decomposition in physics
  • Learn about relative motion in two dimensions
  • Explore trigonometric identities for angle calculations
  • Practice problems involving relative velocity in nautical contexts
USEFUL FOR

Students studying physics, particularly in mechanics and kinematics, as well as anyone interested in navigation and maritime velocity calculations.

jwxie
Messages
278
Reaction score
0

Homework Statement



Two ships, one moving 15 degree west of north with a speed 25 mi/h., the second moving 25 degree south of west with a speed 20 mi/h. relative to water pass each other. Find the velocity of the second ship relative to the first ship (magnitude and direction).

Homework Equations



V1 + r = V2
V2 - V1 = r

The Attempt at a Solution



I want to confirm on this.

My approach is using this relation.
V1 + r = V2
and so V2 - V1 = r, where r is the velocity we are looking for of our problem.

Then I will take components, x and y, and find sqrt(x^2+y^2) and direction tan-1 y/x
 
Physics news on Phys.org
Hi jwxie! :smile:

(have a square-root: √ and try using the X2 and X2 tags just above the Reply box :wink:)
jwxie said:
My approach is using this relation.
V1 + r = V2
and so V2 - V1 = r, where r is the velocity we are looking for of our problem.

Then I will take components, x and y, and find sqrt(x^2+y^2) and direction tan-1 y/x

Yes, that's exactly right! :smile:

(btw, I wouldn't use r, I'd stick to the same area of the alphabet, and use v12 or u or w :wink:)
 
Hi, tiny, thank you for your confirmation. My friend had an exam and he doubted about my explanation. Thank you!

I will make sure I check all the synatx ^^
 

Similar threads

Replies
14
Views
2K
Replies
40
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
14
Views
3K
Replies
2
Views
4K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K