What is the velocity vector after a pinball bounces off a baffle?

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Discussion Overview

The discussion centers on determining the velocity vector of a pinball after it bounces off a baffle in a purely elastic collision. Participants explore mathematical approaches and concepts related to vector addition and the behavior of velocities during elastic collisions.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant seeks assistance in understanding how to calculate the velocity vector after the pinball bounces off the baffle.
  • Another participant suggests using vector addition and the concept of elastic collisions, noting that the velocity along the baffle remains unchanged while the velocity perpendicular to the baffle is reversed.
  • A participant proposes setting up a coordinate system with point P as the origin and point Q at (0, 1), stating that the velocity vector can be expressed as $(v_x, v_y)$ and that after the collision, it becomes $(-v_x, v_y)$.
  • A later reply reiterates the same coordinate system and transformation of the velocity vector after the collision.
  • Another participant explains how to express a vector as a sum of its components, detailing how to calculate the components along and normal to the baffle, and notes that the normal component is reversed upon reflection.

Areas of Agreement / Disagreement

Participants present various methods and perspectives on calculating the velocity vector after the bounce, but no consensus is reached on a definitive answer or approach.

Contextual Notes

The discussion involves assumptions about the nature of the collision being purely elastic and the specific definitions of the coordinate system used, which may affect the interpretation of the velocity components.

WMDhamnekar
MHB
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Hi,

A pinball moving in a plane with velocity s bounces (in a purely elastic impact) from a baffle whose endpoints are p and q. What is the velocity vector after the bounce?

I don't understand how to answer this question? Any math help, hint or even correct answer will be accepted?
 
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Use vectors addition and elastic collision concept that velocity along the baffle will remain unchanged and velocity perpendicular to baffle will get reversed.
 
You can always set up a coordinate with P as origin and Q= (0, 1). The velocity vector of this object can be written $(v_x, v_y)$ in that coordinate system. After an elastic collision with PQ, it's velocity vector is $(-v_x, v_y)$.
 
Country Boy said:
You can always set up a coordinate with P as origin and Q= (0, 1). The velocity vector of this object can be written $(v_x, v_y)$ in that coordinate system. After an elastic collision with PQ, it's velocity vector is $(-v_x, v_y)$.
Hi,

Author has given the following answer to this question. Would you tell me how does the highlighted terms relate to velocity before and after the bounce?

1624939118433.png
 
A vector $u = u_x + u_y $ you can write a vector as a sum of its components.
$(s. \hat{u} ) $ represents the magnitude of the component of vector s along baffle and if you multiply by unit vector $\hat{u}$ you get vector component of s along with the baffle similarly $(s. \hat{v})$ represents the magnitude of the component of vector s normal to baffle and again if you multiply by unit vector $\hat{v}$ you will get vector component of s normal to baffle.
For reflected ray normal gets reversed so the normal vector is expressed with the negative sign there.
 

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