What is the Voltage Compliance Range of a Current Source?

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SUMMARY

The voltage compliance range of a current source is defined as 9V < Vcomp < 10V, based on the calculations involving the load resistor (R_L) and the current (I_L). The circuit operates as a current source when the 8.2K resistor maintains a voltage of +10V. For R_L values ranging from 0 to 8.4K ohms, the circuit remains functional; exceeding this range leads to transistor saturation, affecting performance. The compliance voltage is crucial for ensuring proper load regulation within specified limits.

PREREQUISITES
  • Understanding of current sources and their compliance voltage
  • Familiarity with Ohm's Law and resistor calculations
  • Knowledge of transistor operation, particularly saturation
  • Experience with circuit analysis involving voltage and current relationships
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  • Study the principles of voltage compliance in current sources
  • Learn about transistor saturation and its effects on circuit performance
  • Explore load regulation techniques in constant current power supplies
  • Investigate the impact of varying load resistors on circuit behavior
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Electrical engineers, circuit designers, and students studying electronics who are interested in current source functionality and voltage compliance analysis.

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Thank you for any help that you can offer.

Did I answer all of the questions correctly and thoroughly? Can you please find any errors, and point them out to me so that I can fix them?

Homework Statement



Show that :

VB = 1.6V
VE = 1.0V
IE = 1.0 mA
IL = 1.0 mA
What is the voltage compliance range of the current source?
For what range of load resistors RL will the circuit function as a current source?

https://scontent-a.xx.fbcdn.net/hphotos-prn1/t1.0-9/1012267_10151937081750919_819156677_n.jpg

Homework Equations



RB1/RB2 = {10V - VB}/VB
...................
IL = IE = VB - 0.6/RE
.................
VLimit < Vcomp < {VRE/RE}RL = 1.03mA[/B]
.....................
iout = Vin/RE
............

The Attempt at a Solution



2(a)1

RB1/RB2 = {10V - VB}/VB
..................
8.2k/1.6k = {10V - VB}/VB
.............
5.125VB = {10V - VB}
............
5.125VB + VB = 10V
............
6.125VB = 10V
........
VB = 10V/6.125
.......
VB = 1.63V
......

2(a)2
.......
IL = IE = VB - 0.6/RE
.................
IL = IE = 1.63 - 0.6/1000k
.............
IL = IE = 1.03/1000k
............
IL = IE = 1.03mA
..........
VB - VBE = VE
.............
VE = 1.03V
......
VE/RE = 1.03V/1000k
............
IE = VE/RE = 1.03mA
...............


What is the voltage compliance range of the current source?

The device is in comlpliance when:

VLimit < Vcomp < {VRE/RE}RL = 1.03mA[/B]
...............
VCC - ILRE < Vcomp < {VRE/RE}{VCC/IE}
.................
10V - (0.001A)(1000[ohms]) < Vcomp < {1V/1000[ohms]}{10V/0.001A}
.....................
10V - 1V < Vcomp < 10V
.........
9V < Vcomp < 10V
.........


For what range of load resistors RL will the circuit function as a current source?

The range of load resistors can be found by:

iout = Vin/RE
............
9V/1000[ohms] < Vcomp/RL[ohms] < 10V/1000[ohms]
...................
Your assistance will be greatly appreciated
 
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"Compliance range" needs to be better defined.

The circuit is a current source for R_L only if the 8.2K resistor stays at +10V.
Then you can determine how low Vcc to R_L can be before the transistor saturates.

There is in addition a high voltage limit due to the breakdown voltages of the transistor, but that can't be determined with the data you're given.

The last question's answer depends on the voltage to R_L as well as the value of R_L, so I guess assume Vcc = 10V for R_L.
 
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rude man said:
"Compliance range" needs to be better defined.

The circuit is a current source for R_L only if the 8.2K resistor stays at +10V.
Then you can determine how low Vcc to R_L can be before the transistor saturates.

There is in addition a high voltage limit due to the breakdown voltages of the transistor, but that can't be determined with the data you're given.

The last question's answer depends on the voltage to R_L as well as the value of R_L, so I guess assume Vcc = 10V for R_L.


@rude man


Thank you. I will make corrections.
 
@rude man,


If the compliance voltage is the range of output voltage in a constant current (dc) power supply over which the load regulation is within certain limits, how can I use this knowledge to verify that my last answer is correct. Can the variable load resistor range from 0 to 8k4 ohms. If it is higher than that, what will happen?

Thank you
 
If your load is 8000 ohms, what is the collector voltage going to be?
If it's 9000 ohms, what then?

Hint: if the emitter to collector voltage is < about 0.2V the transistor is in saturation.

BTW this is not voltage compliance. It assumes the voltage to RL is a constant +10V.

Voltage compliance is a function of R_L. Try to figure out how low the voltage at the top of R_L can be for a given R_L.
 

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