MHB What is the Volume of a Solid with Squares as Cross Sections?

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The discussion focuses on calculating the volume of a solid with square cross-sections, where the base region R is defined by the curves y = x^2 and y = x in the first quadrant. The volume is derived using the formula for the area of a square, leading to the integral V = ∫(x - x^2)² dx from 0 to 1. The user initially computes the integral and arrives at a volume of 1/30, which does not match any provided answer choices. After correcting a potential typo, the user suggests that the correct volume might be closer to 0.033. The discussion emphasizes understanding the relationship between the area of the squares and the volume of the solid.
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Let R be the region in the first quadrant bounded below by the graph of $y = x^2$ and above by the graph of
$y=x$. R is the base of a solid whose cross sections perpendicular to the x-axis are squares
\item What is the volume of the solid?
A 0.129
B 0.300
C 0.333
D 700
E 1.271ok I didnt understand what "square area" meant
 
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I would first write:

$$dV=(x-x^2)^2\,dx=(x^2-2x^3+x^4)\,dx$$

Hence:

$$V=\int_0^1 x^2-2x^3+x^4\,dx=\frac{1}{30}$$

This seems to be none of the given choices.
 
probably C 0.033 after adjusting the typo

so that was how the squares is implemented 🐮
 

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