MHB What is the Volume of a Solid with Squares as Cross Sections?

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SUMMARY

The volume of the solid with square cross sections, bounded by the curves $y = x^2$ and $y = x$ in the first quadrant, is calculated using the integral of the square of the difference between the two functions. The correct volume is derived from the equation $$dV=(x-x^2)^2\,dx$$ leading to the integral $$V=\int_0^1 (x^2-2x^3+x^4)\,dx$$ which evaluates to $\frac{1}{30}$. This result does not match any of the provided answer choices, indicating a potential typo in the options.

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karush
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Let R be the region in the first quadrant bounded below by the graph of $y = x^2$ and above by the graph of
$y=x$. R is the base of a solid whose cross sections perpendicular to the x-axis are squares
\item What is the volume of the solid?
A 0.129
B 0.300
C 0.333
D 700
E 1.271ok I didnt understand what "square area" meant
 
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I would first write:

$$dV=(x-x^2)^2\,dx=(x^2-2x^3+x^4)\,dx$$

Hence:

$$V=\int_0^1 x^2-2x^3+x^4\,dx=\frac{1}{30}$$

This seems to be none of the given choices.
 
probably C 0.033 after adjusting the typo

so that was how the squares is implemented 🐮
 
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