The volume of a cylindrical tank with an 8 ft diameter and a height of 15 ft is calculated using the formula V = Ah, where A is the cross-sectional area. The correct area A is determined using A = πD²/4, resulting in A = 50.24 ft². Therefore, the volume V is calculated as V = (50.24 ft²)(15 ft), yielding a final volume of V = 753.6 ft³. It is important to use a precise value for π, as 3.14 is merely an approximation.
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jim1174 said:Homework Statement
What is the volume of a tank that is 8 ft in diameter and 15 feet high
Homework Equations
The Attempt at a Solution
13.4 X 24ft X 15ft= 1130.4
This looks good.jim1174 said:D = diameter = 8 ft
h = height = 15 ft
A = cross-sectional area = to be determined
V = volume = to be determined
A = πD²/4
A = (3.14)(8 ft)²/4
A = 50.3 ft²
V = Ah
V = (50.3 ft²)(15 ft)
V = 754 ft³
jim1174 said:D = diameter = 8 ft
h = height = 15 ft
A = cross-sectional area = to be determined
V = volume = to be determined
A = πD²/4
A = (3.14)(8 ft)²/4
A = 50.3 ft²
V = Ah
V = (50.3 ft²)(15 ft)
V = 754 ft³
Just to clarify your initial work, in your first expression above, you have 20 ft where it should have been 15 ft. I understand that "(4ft) 2" is supposed to be 42, which can also be written as 4^2.jim1174 said:. The attempt at a solution
Π x (4ft) 2 x 20ft
3.14 X 24ft x 15ft = 1130.4