A man standing x ft. from a light pole, length of man's shadow?

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Homework Help Overview

The problem involves a man standing a distance x from a light pole, with the goal of expressing the length of his shadow L as a function of x. The scenario includes a man who is 6 feet tall and a light pole that is 15 feet high, and it requires the application of similar triangles without the use of trigonometry.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of similar triangles to relate the height of the man and the light pole to the lengths of the shadows. There is a focus on setting up the proportions correctly and questioning the validity of the derived expressions for L.

Discussion Status

Some participants confirm the original poster's approach and calculations, suggesting that the discrepancy with the book's answer may be a typo. There appears to be a productive exchange regarding the setup of the problem and the reasoning behind the calculations.

Contextual Notes

There is an emphasis on the restriction of not using trigonometry and the need to express the shadow length as a function of the distance from the pole. The potential for a typo in the textbook solution is also noted.

Feodalherren
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Homework Statement


A man 6ft. tall is standing x ft. from a light pole 15 ft. high. Express the length of the man's shadow L as a function of x.

Homework Equations


Pre-Calc.
NO TRIG


The Attempt at a Solution


I assumed that the man's shadow creates another like triangle within in the larger one. The base of the large triangle is L + x and the height is 15 ft.
The base of the small triangle is L and the height 6 ft.

I set 15/(L+x) = (6/L) and solved for L. My solution was L(x)=(2/3)x, however, the book says it's L(x)=(3/2)x. Is it a typo or am I doing something wrong?
 
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Feodalherren said:

Homework Statement


A man 6ft. tall is standing x ft. from a light pole 15 ft. high. Express the length of the man's shadow L as a function of x.

Homework Equations


Pre-Calc.
NO TRIG


The Attempt at a Solution


I assumed that the man's shadow creates another like triangle within in the larger one. The base of the large triangle is L + x and the height is 15 ft.
The base of the small triangle is L and the height 6 ft.

I set 15/(L+x) = (6/L) and solved for L. My solution was L(x)=(2/3)x, however, the book says it's L(x)=(3/2)x. Is it a typo or am I doing something wrong?

Your process is correct and your answer is correct
 
Feodalherren said:
I assumed that the man's shadow creates another like triangle within in the larger one. The base of the large triangle is L + x and the height is 15 ft.
The base of the small triangle is L and the height 6 ft.

I set 15/(L+x) = (6/L) and solved for L. My solution was L(x)=(2/3)x, however, the book says it's L(x)=(3/2)x. Is it a typo or am I doing something wrong?
Looks fine to me. The book's solution is a typo.

EDIT: Oops, beaten to it by phinds. :wink:
 
Thanks guys.
 

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