What is the weight of a hollow sphere underwater?

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SUMMARY

The weight of a hollow sphere underwater, with an average density of 3 g/cm3 and a mass of 120g, is calculated to be 0.8 N. To determine this, the mass must first be converted to SI units, resulting in 0.12 kg. The weight underwater is derived from the net force, which accounts for the downward gravitational force and the upward buoyant force, calculated using the volume of the sphere and the density of water.

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Homework Statement



A hollow sphere has average density of 3 g/cm^3 and a mass of 120g. What will the sphere weight under water?

correct answer: 0.8

Homework Equations



d=m/v

w=mg


The Attempt at a Solution



I converted 120g into kg and then used w=mg to find weight on land. however, this does get 0.8N underwater. Please help thanks!
 
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first, change all the units to SI units, giving you:
3000 kg/m3 for the sphere's density
0.12 kg for its mass

to possibly calculate the sphere's weight underwater, you must calculate the net force of the sphere's weight downwards and buoyancy upwards

buoyant force is equal to the weight of the water displaced by the ball, thus you calculate the weight by using the mass of the water displaced, found by:
1. density of water
2. the volume of water displaced, which is equal to the volume of the sphere since it is fully submerged
 
got it, thanks!
 

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