So I have tried to solve this problem but my answer keeps turning out to be wrong.. Someone please tell me what I am doing wrong?
A 0.484 mm diameter hole is illuminated by light of wavelength 556.0 nm. What is the width (in mm) of the central maximum on a screen 3.45 m behind the slit?
The width of the central maximum is given by W= (2λL)/(a)
So I have wavelength λ=556x10^-9 m
Screen distance L=3.45 m
And slit width= .484x10^-3 m
The Attempt at a Solution
So the width of the central maximum = ((2)(556x10^-9)(3.45))/(0.484x10^-3) = 7.926 mm