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## Homework Statement

So I have tried to solve this problem but my answer keeps turning out to be wrong.. Someone please tell me what I am doing wrong?

A 0.484 mm diameter hole is illuminated by light of wavelength 556.0 nm. What is the width (in mm) of the central maximum on a screen 3.45 m behind the slit?

## Homework Equations

The width of the central maximum is given by W= (2λL)/(a)

So I have wavelength λ=556x10^-9 m

Screen distance L=3.45 m

And slit width= .484x10^-3 m

## The Attempt at a Solution

So the width of the central maximum = ((2)(556x10^-9)(3.45))/(0.484x10^-3) = 7.926 mm