What is the work done by the force field on a particle moving along a helix?

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SUMMARY

The work done by the force field F(x, y, z) = 3xi + 3yj + 7k on a particle moving along the helix r(t) = 4 cos(t)i + 4 sin(t)j + 4tk, for 0 ≤ t ≤ 2π, is calculated using the line integral of the force field along the curve. The correct evaluation of the integral ∫F·dr results in a total work of 56π. The initial miscalculation of 48π was corrected upon realizing the integral simplifies to ∫(28)dt over the specified limits.

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Homework Statement



Find the work done by the force field F(x, y, z) = 3xi +3yj + 7k on a particle that moves along the helix r(t) = 4 cos(t)i + 4 sin(t)j + 4tk, 0 ≤ t ≤ 2π (As in the previous problem, recall that the work of the force F on the helix corresponds to the circulation of this vector field along the curve).


Homework Equations





The Attempt at a Solution



F(x, y, z) = 3xi +3yj + 7k
r(t) = 4 cos(t)i + 4 sin(t)j + 4tk , 0 ≤ t ≤ 2π
r'(t) = -4sin(t)i + 4cos(t)j + 4

\intF(dot)dr
\int(-48cos(t)sin(t) + 48cos(t)sin(t) + 28)dt
\int (28)dt

With the integral going from 0 to 2pi I thought the answer would be 48pi, but it's not.
 
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Nevermind, I got it, it's 28*2pi
 

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