What is the Work Involved in Lifting and Moving a Box with a Crane?

The crane needs to exert a force equal to the weight of the box, but in the opposite direction. This cancels out the gravitational force, allowing the crane to lift the box. In summary, the problem involves a crane lifting a box with a weight of 8400N to a height of 35m and then moving it horizontally for a distance of 10m with no friction. To find the work done, the formula W=W1+W2 is used, with W1 representing the work done in elevating the box and W2 representing the work done in moving it. To find W1, the force F1 must be found, which is equal to the weight of the box minus the force of gravity. To find
  • #1
Adrian379
6
0
1. The problem statement, all variables and given/known
G=8400N
h=35m
d=10m
g=10m/s^2

A crane elevate a box with G=8400N at h=35. After this, the box is moved horizontal on distance 10m. No friction.

Work = ?
ps. Sorry for bad English.

Homework Equations


I think that W=W1 ( work on elevating ) + W2 ( work on moving ).
W1=F1*h and W2=F2*d

In the first I must tu find F1.
F=F1-G ==> F1=G-F=G-ma

Now, F2:
F=F2==> F2=m*a.

W=F1+F2=G-ma+m*a.

But I don't know a...

The Attempt at a Solution


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I know I am bad but I want to learn. What can I do to solve this exercice ? Thank you very much !
 
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  • #2
Hello Adrian, :welcome:

Assume the lifting goes very slowly. So the only force that is needed for that is ##mg## = G . Keep the direction of the force in mind.
(why do I say that?).
 
  • #3
Because F = -G ? Or.. F is a little bit stronger that G to lift ?

8bz1CVp.png
 
Last edited:
  • #4
//Sorry for x2 post.
 
  • #5
Adrian379 said:
Because F = -G ?
That is what is meant, yes.
 

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