What is wrong with following physics equations? (velocity and acceleration)

So the correct equation should be Vf=Vi + at. The mistake was that in the original equation, the 1/2 was missing in front of Vi, making the equation incorrect. This was corrected in the revised equation. The fundamental units of acceleration are meters per second squared (m/s^2). In summary, the conversation discusses the equation for average velocity, Vavg, which can be calculated using different formulas involving initial velocity (Vi), final velocity (Vf), distance (h), and time (t). However, the original equation was incorrect as it was missing a 1/2 in front of Vi, and the correct equation is Vf=Vi + at. The fundamental units of acceleration are meters per second squared (
  • #1
Selfphysicslearner
3
2
vavg=(Vi+Vf)/2
vavg=h/t
then vavg*t=h
h=(Vi+Vf)/2 * t
Vf=at
(Vit+at2)*1/2=h
But formula on every resource I found says it should be;
(Vit+at2*1/2)=h
What mistake did I do ?
 

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  • #2
Selfphysicslearner said:
Vf=at
Is it?
Are you missing anything here?
 
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  • #3
Selfphysicslearner said:
Vf=at
This is not generally correct.
 
  • #4
cnh1995 said:
Is it?
Are you missing anything here?
I see it must be actually:Vf=Vi+at then there is 2 Vi in formula which eliminates 1/2 multiplied makes it
h=1/at^2 +2*1/2Vi
 
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  • #5
What are the fundamental units of acceleration?
 
  • #6
Selfphysicslearner said:
vavg=(Vi+Vf)/2
vavg=h/t
then vavg*t=h
h=(Vi+Vf)/2 * t
Vf=at
(Vit+at2)*1/2=h
But formula on every resource I found says it should be;
(Vit+at2*1/2)=h
What mistake did I do ?
Vf=at , this equation means final velocity = acceleration * time. This can happen only if initial velocity is 0, but in the equation Vi is the initial velocity and Vi is not 0 as per the equations wrriten.
 

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