What is wrong with our assumptions?

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I am trying to do a simple experiment that estimates the mass of an object based on how an Atwood machine reacts when it is added to one side.

For this experiment we have a pulley with 200-gram masses on either side of the rope. We then set it up so that the right mass was exactly one meter from the floor. Then we would attach the unknown mass to the other time, and measure the time in seconds it took for it to hit the floor.

From this data we calculated that the acceleration was (1 meter / (seconds to fall)^2). We then put it into the following formula.
Atwood machine acceleration formula written as a = g((m2 - m1)/(m1 + m2)), with a on the left and g multiplying a fraction in parentheses.

I really don't know where we got this formula from. I also don't know wether the a on one side is expressing acceleration of the system, or just one of the masses.

Since m1 and m2 are both 200 grams we were able to simplify the formula. While simplifying we considered that m2 would be (m1 + mu) (mu being the unknown mass). We then got this formula:
Formula a = g(m_u / (2m_1 + m_u)) with a on the left, g multiplied by a fraction whose numerator is m subscript u and denominator is 2m subscript 1 plus m subscript u.


We tried out our first mass and it took it 3.3 seconds to travel one meter.
We plugged everyhing into the formula and got

Unfortunately this did not work out for us. We converted grams to kilograms and substituted everything in. We got a calculated mass that was way too low, the objects actual weight is 12 grams. What did we mess up?
 
cubby208 said:
I am trying to do a simple experiment that estimates the mass of an object based on how an Atwood machine reacts when it is added to one side.

For this experiment we have a pulley with 200-gram masses on either side of the rope. We then set it up so that the right mass was exactly one meter from the floor. Then we would attach the unknown mass to the other time, and measure the time in seconds it took for it to hit the floor.

From this data we calculated that the acceleration was (1 meter / (seconds to fall)^2). We then put it into the following formula.
Equation a = g((m2 - m1)/(m1 + m2)), with a on the left and g multiplied by a fraction on the right, where the numerator is m2 minus m1 and the denominator is m1 plus m2.

I really don't know where we got this formula from. I also don't know wether the a on one side is expressing acceleration of the system, or just one of the masses.

Since m1 and m2 are both 200 grams we were able to simplify the formula. While simplifying we considered that m2 would be (m1 + mu) (mu being the unknown mass). We then got this formula:
Formula a = g(m_u / (2m_1 + m_u)) with a on the left, g multiplying a large parenthesised fraction whose numerator is m_u and denominator is 2m_1 + m_u.


We tried out our first mass and it took it 3.3 seconds to travel one meter.
We plugged everyhing into the formula and got

Unfortunately this did not work out for us. We converted grams to kilograms and substituted everything in. We got a calculated mass that was way too low, the objects actual weight is 12 grams. What did we mess up?

First, if you don't know where a formula comes from you should see if you can derive it.

Why don't you draw a force diagram for the masses and try to come up with it, it'll clear up what it's actually trying to say.

Edit: Okay I reread it, and think you're saying that the .2kg mass is still there. in which case, your simplification is okay.

What did you get for acceleration? And the unknown mass?

I'm going to report this post, as I think it would be more appropriately placed in homework.
 
Last edited:
cubby208 said:
From this data we calculated that the acceleration was (1 meter / (seconds to fall)^2).
You're missing a factor of 2 there. If the distance to fall is ##h##, the time taken is ##t## and the acceleration is ##a##, then ##h=\frac{1}{2} at^2##, which gives ##a=2h/t^2##.

We then put it into the following formula.
Equation a = g((m2 - m1)/(m1 + m2)), with m2 - m1 over m1 + m2 inside parentheses multiplied by g.

I really don't know where we got this formula from. I also don't know wether the a on one side is expressing acceleration of the system, or just one of the masses.
The two masses are connected by a string that doesn't stretch, so a is the magnitude of the acceleration of either one of the masses. One accelerates downwards while the other accelerates upwards at the same rate.

Since m1 and m2 are both 200 grams we were able to simplify the formula. While simplifying we considered that m2 would be (m1 + mu) (mu being the unknown mass). We then got this formula:
Equation written in plain type: a = g times the fraction m_u over (2m_1 + m_u), with the fraction enclosed in large parentheses.
Fine.

We tried out our first mass and it took it 3.3 seconds to travel one meter.
We plugged everyhing into the formula and got ...
Got what? Is something missing there?

Unfortunately this did not work out for us. We converted grams to kilograms and substituted everything in. We got a calculated mass that was way too low, the objects actual weight is 12 grams. What did we mess up?
Are you trying to solve for ##m_u##, then, using the measured value of ##a##? Re-arranging your second equation gives $$m_u = \frac{2 m_1 a}{g-a}$$. Does that help?