What is wrong with this differentiation?

[pc2-brazil]

Homework Statement

Find dy/dt, given:
$$y=x^2-5x+1$$
$$x=s^3-2s+1$$
$$s=\sqrt{t^2+1}$$

2. The attempt at a solution
I am trying to use the chain rule for the case where y is a function of x, x is a function of s and s is a function of t, like below:
$$\frac{dy}{dt}=\frac{dy}{dx}\frac{dx}{ds}\frac{ds}{dt}$$
So:
$$\frac{dy}{dt}=(2x-5)(3s^2-2)(\frac{t}{\sqrt{t^2+1}})$$
But this gives (substituting x and s for their values as functions of t)
$$6t^5-4t^3-\frac{3t}{\sqrt{t^2+1}}-\frac{9t^3}{\sqrt{t^2+1}}-2t$$
which is not the correct result. The correct result is:
$$6t^5-4t^3-9t\sqrt{t^2+1}+\frac{6t}{\sqrt{t^2+1}}-2t$$
What is wrong?

Thank you in advance.

 

[pc2-brazil]

Never mind. After doing some manipulations I found that apparently both results are equal, because these two terms of the answer given as correct:
$$-9t\sqrt{t^2+1}+\frac{6t}{\sqrt{t^2+1}}$$
after some manipulation:
$$-9t\sqrt{t^2+1}+\frac{6t}{\sqrt{t^2+1}}=\frac{-9t(t^2+1)+6t}{\sqrt{t^2+1}}=\frac{-9t^3-3t}{\sqrt{t^2+1}}$$
become the two terms of the answer I found.