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What is Young's modulus for this alloy of titanium?

  1. May 27, 2008 #1
    1. The problem statement, all variables and given/known data
    A hanging wire made of an alloy of titanium with diameter 0.15 cm is initially 2.8 m long. When a 109 kg mass is hung from it, the wire stretches an amount 1.41 cm. A mole of titanium has a mass of 48 grams, and its density is 4.54 g/cm^3.

    Based on these experimental measurements, what is Young's modulus for this alloy of titanium?
    From the mass of one mole and the density you can find the length of the interatomic bond (diameter of one atom). This is 2.60E-10 m for titanium. What is the k{s,i}?

    2. Relevant equations
    k{s,i}: stiffness of an interatomic bond in a solid.
    Y= stress/strain = (tension force/cross section area)/(change of Length/Length)
    Y = ((k{s,i}*s)/diameter^2)/(s/diameter) = k{s,i}/diameter


    3. The attempt at a solution
    stress = changeL/L = .0141m/2.8m = 5.035714E-3
    strain = F{T}/A = 9.81*mass / pi*(7.5E-4)^2 = 5.532E11
    4.5g/cm^3 = 4.5E3kg/m^3
    (mass = Density*length^3 = 4.5E3kg/m^3*(2.8 m)^3 = 99662.08)

    stress/strain = Y = 9.10195E-15


    I'm pretty sure that's the wrong answer.
     
  2. jcsd
  3. May 27, 2008 #2

    alphysicist

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    Homework Helper

    Hi badwallpaper0,

    The stress is F/A, and the strain is (change in L/L); you seem to have these reversed.

    Also, what number did you use for the mass in calculating F/A? I don't see how you got the result 5.532e11.
     
  4. May 27, 2008 #3
    Hey alphysicist,
    First of all, thank you for the help.
    Ok, I redid the problem making
    mass = density*length^3 = 4.54E3 kg/m^3 * 2.8^3 = 9.966208E4
    stress=F{t}/A = 9.81*mass / pi*(7.5E-4)^2 = 5.5325E11
    strain=.0141m/2.8m = 5.0357E-3

    stress/strain = 5.53256E11/5.0357E-3 = 1.098665E14

    I changed the stress and strain as you suggested, and I redid the calculation for mass.
    Does that seem like a reasonable/correct answer?
     
  5. May 27, 2008 #4

    alphysicist

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    I think there are a couple of issues. First, to calculate the mass of the wire, you would multiply the density times the volume of the wire. The mass you found using length^3 would be the mass of a cube of titanium 2.8 m on each side. But this wire is a skinny cylinder, and so it's volume is its length times its cross-sectional area.

    But the mass of the wire is not what goes into the Young's modulus calculation. The idea is this: first the wire had a length of 2.8 m, then because somebody hung a 109 kg mass on it, it stretched by 1.41 cm. So the force that we use in calculating the stress is the force that makes the wire stretch, so here the mass needs to be 109 kg (because the force causing the stretch is the weight of that mass).

    (The reason we don't need to include the weight of the wire at all is because whatever effect it had on the length was already accounted for in the original 2.8 m length. Only the extra mass caused the extra length.)
     
  6. May 27, 2008 #5
    That makes sense.

    So instead of trying to figure out the wire's mass we would find the mass of the weight added to the end (though in this case it's given).

    So it's simply (9.81m/s*109kg)/(pi*(7.5E-4)^2) = 6.0509E8 = stress

    6.0509E8/5.0357E-3 = 1.2016E11 - this seems like a large number, though titanium is 105-120 GPa.

    I think the units should be kg/(ms^2), though mine doesn't seem to work out that way.
     
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