What Kind of Triangle is ABC in a Square with an Isosceles Triangle?

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SUMMARY

The triangle ABC, formed within square ABDE with point C creating an isosceles triangle CDE (with angles of 15 degrees at D and E), is definitively an equilateral triangle. This conclusion is supported by the construction of point F, which is positioned to ensure triangle CDF is congruent to triangle CDE. The proof relies on the application of various Euclidean theorems, particularly the Law of Cosines and properties of perpendicular lines, as outlined in Coxeter's Geometry.

PREREQUISITES
  • Understanding of Euclidean geometry principles
  • Familiarity with the Law of Cosines
  • Knowledge of triangle congruence criteria
  • Basic concepts of angles and perpendicular lines
NEXT STEPS
  • Study the Law of Cosines in detail
  • Explore triangle congruence theorems such as SSS and SAS
  • Review properties of isosceles and equilateral triangles
  • Investigate geometric constructions using compass and straightedge
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Students of geometry, educators teaching Euclidean principles, and anyone interested in geometric proofs and constructions.

chaotixmonjuish
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I have this question:

Inside a square ABDE, take a point C so that CDE is an isosceles triangle with angles 15 degrees at D and E. What kind of triangle is ABC?

I put C close to the bottom to get my isosceles triangle. According to the answer in back, the triangle ABC is equilateral. The hint that went along with the answer is pick a point F to make a triangle congruent to triangle CDE. Are there theorems that I am missing to see how this could work out? I've spent a while on this and I feel like I'm missing something obvious.
 
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have you tried law of cosines?
 
In this exercise, I have to do the proof using various Euclidean theorems. It's a practice exercise from Coxeter's Geometry book. The hint says to create a point F such that BF is perpendicular to CD aof the equilateral triangle CDF. Hence BC=BD=AB: and ABC is equilateral

I'm not sure how that happens
 

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