What Makes Complex Power Functions Confusing?

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The discussion centers on the complexities of taking powers of complex variables, specifically the formula (z^a)^b = z^{ab} e^{2kiπb}. The user questions whether (z^a)^{1/a} equals z in general cases, leading to the conclusion that it does not due to the non-uniqueness of complex powers for non-integer exponents. This non-uniqueness arises from the branch cut in the definition of complex powers, where z^a is expressed as exp(a*log(z)). Understanding this concept is crucial for grasping the behavior of complex power functions.

PREREQUISITES
  • Complex analysis fundamentals
  • Understanding of complex logarithms
  • Knowledge of branch cuts in complex functions
  • Familiarity with exponentiation of complex numbers
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  • Study the properties of complex logarithms and their implications
  • Explore the concept of branch cuts in complex analysis
  • Learn about the multi-valued nature of complex functions
  • Investigate real number exponentiation and its conventions
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Students and professionals in mathematics, particularly those studying complex analysis, as well as educators seeking to clarify the intricacies of complex power functions.

giokara
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Hi

I just got an introduction in complex analysis and some things are still not so clear. What troubles me the most is a property of taking the power of a complex variable. We have seen that:
[tex](z^a)^b = z^{ab} e^{2ki\pi b}[/tex]
I can prove that formula but I can't understand it. Does this mean that when we take b = 1/a,
[tex](z^a)^{\frac{1}{a}} \neq z[/tex]
in the general case?
If that is true (which I assume), is there a logical explanation for it? I see it comes from the branch cut that is inserted to use the definition of a power (z^a = exp(a*log(z))) but I can't see why exactly this results in this strange property for a complex powerfunction..

Thx!
 
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giokara said:
Hi

I just got an introduction in complex analysis and some things are still not so clear. What troubles me the most is a property of taking the power of a complex variable. We have seen that:
[tex](z^a)^b = z^{ab} e^{2ki\pi b}[/tex]
I can prove that formula but I can't understand it. Does this mean that when we take b = 1/a,
[tex](z^a)^{\frac{1}{a}} \neq z[/tex]
in the general case?
If that is true (which I assume), is there a logical explanation for it? I see it comes from the branch cut that is inserted to use the definition of a power (z^a = exp(a*log(z))) but I can't see why exactly this results in this strange property for a complex powerfunction..

Thx!
It's not all that mysterious, even in the reals. Take z = -1, a = 2. What do you get?

The main thing you need to remember about complex powers is that z^a is not uniquely defined for non-integer a. Again this is not all that mysterious. In the reals we define x^(1/2) to be the positive square root, but that is only a convention which serves to make the identities work out nicely. Sometimes the negative square root is the "right answer". For the complex numbers, no convention works-- so you have to learn to live with multiple answers for the square root and other non-integer powers.
 
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