What Metal Is the Wire Made Of Based on Its Resistivity?

Click For Summary

Homework Help Overview

The discussion revolves around identifying the metal composition of a wire based on its resistivity, given specific parameters such as length, diameter, voltage, and current. The problem is situated within the context of electrical resistance and resistivity calculations.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss calculating resistance using the formula R=p(l/A) and attempt to derive the resistivity from given values. There are questions regarding the correct calculation of the cross-sectional area of the wire, with some participants noting errors in the area calculation.

Discussion Status

Several participants are actively engaging in the problem, with attempts to calculate resistivity leading to discrepancies in results. Guidance has been offered regarding the correct method to calculate the cross-sectional area, indicating a productive direction in the discussion.

Contextual Notes

Participants are working under the assumption that the wire's material can be identified from a set list of metals, and there is a focus on ensuring accurate calculations based on the provided dimensions and equations.

goWlfpack
Messages
51
Reaction score
0

Homework Statement



A wire, 50.0 m long and 2.00 mm in diameter is connected to a source with a potential difference of 9.11 V, and the current is found to be 23.45 A. Assume a temperature of 20°C and using Table 17.1, identify the metal out of which the wire is made of.

Homework Equations



R=p(l/A)

where R is the resistance p is the coefficient of resistivity, l is the length and A is the area

The Attempt at a Solution



ok since we are solving for p first i found R by the equation V=IR and found R to be .388
next i found the area using the surface area of a cylinder and found that to be .628
next i divided length by .628 and found that to be 79.618
so then i divided .388/79.618 and got 4.8*10^-3
thats the right magnitude but it does match any of my options coefficients.

the problem let's me choose whether the metal is gold, silver, copper, or iron.
 
Physics news on Phys.org
goWlfpack said:

Homework Statement



A wire, 50.0 m long and 2.00 mm in diameter is connected to a source with a potential difference of 9.11 V, and the current is found to be 23.45 A. Assume a temperature of 20°C and using Table 17.1, identify the metal out of which the wire is made of.

Homework Equations



R=p(l/A)

where R is the resistance p is the coefficient of resistivity, l is the length and A is the area

The Attempt at a Solution



ok since we are solving for p first i found R by the equation V=IR and found R to be .388
next i found the area using the surface area of a cylinder and found that to be .628

wrong area. you want the cross-sectional area of the wire

next i divided length by .628 and found that to be 79.618
so then i divided .388/79.618 and got 4.8*10^-3
thats the right magnitude but it does match any of my options coefficients.

the problem let's me choose whether the metal is gold, silver, copper, or iron.
 
ugh ok i got the area by .002*.002*3.14 = .00001256
then i divided 50/.00001256 and got 3980891.72
so then i divided my R .388 by 3980891.72 an got 9.74e-8
not right...
 
please help i really don't understand why this is still wrong...
 
you still have the wrong number for the area. The *diameter* is 0.002. The *radius* is 0.001.
You used Area=diameter*diameter*Pi, which is wrong.

Area=radius*radius*Pi
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 4 ·
Replies
4
Views
4K
Replies
6
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
6
Views
2K