What mistake did Mindy make when solving this quadratic equation?

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Homework Statement


Mindy solves the problem (x+4)(x-3)=8 by setting x+4=8 and x-3=8, thereby getting the solutin x=4 from both equations. she checks her answer by substituting x=4 into the original equation and finds that it works. She concludes that this quadratic equation has only one solution. if we check x=-5, it also works. she lost a solution. WHAT MISTAKE DID MINDY MAKE? WHAT MIGHT SHE NOT UNDERSTAND? WHAT PROPERTY OF FIELDS/INTEGRAL DOMAINS IS MINDY'S MISTAKE RELATED TO?


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The Attempt at a Solution


If she were to first FOIL, subtract 8 from both sides, and solve for x, then she would get both solutions. BUT, i am stuck in explaining what she might not understand and what fields/integral domains is her mistake related to...
 
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I'm thinking that this has to do with Zero Divisors. Specifically the nonexistence of them. Does that help?
 
that makes sense as far as explaining her misunderstanding...but what about the property of fields/integral domains that her mistake is related to?
 
Mindy is assuming "if ab= c then a= c or b= c" which is not true. It is a mistaken version of the "zero product" rule that says "if ab= 0 then a= 0 or b= 0". That, in turn is true because if [itex]a\ne 0[/itex] we can divide by it getting b= 0 and the reverse. That is where "no zero divisors" in a field is applied and where Mindy's mistake is. "No zero divisors" does NOT mean "no c divisors" for c non-zero.
 
halvizo1031 said:

Homework Statement


Mindy solves the problem (x+4)(x-3)=8 by setting x+4=8 and x-3=8, thereby getting the solutin x=4 from both equations.

Um, you don't get x=4 from both equations. If x-3=8, x=11, not 4.
 
you are correct that she "should" get 4 and 11 but i guess it doesn't matter since her process and reasoning is incorrect. unless the professor made a mistake in typing this question...thank you both for your input.