What Pressure Does a 0.5" ID Tube Have on a 39"x75" Area?

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The discussion centers on calculating the pressure exerted by a 180 lbs weight on a 39"x75" area, resulting in a pressure of 0.0615 psi using the formula P=F/A. It clarifies that if the box is flexible, the pressure at the tube's opening would match this value. However, if the box has stiffness, the pressure distribution changes, with most of the weight supported by the sides, rendering the tube diameter irrelevant to the pressure calculation.

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futbalfantic
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I have a 39"x75"x0.75" area that has 180lbs resting ontop of it. According to P=F/A or P=180lbs/2,925 I^2 therefore P=0.0615... If a tube comes off of the side of the "box" that is 0.5" inside diameter would this have a pressure of 0.0615 or would I find this pressure some other way?
 
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If the sides of the box are completely flexible (for example the "box" is just a sealed bag full of air) , then yes. This is how car tires support the weight of the car.

If the box has any stiffness, then some of the 180 lbf will be supported by the forces in the sides. If the box is stiff enough so it doesn't bend much, most likely nearly all the 180lbf would be suppored by the sides, and the change in pressure would be very small.

The diameter of the tube is irrelevant.
 
Yeah I was thinking of a sealed bag full of air.
 

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