The discussion revolves around calculating the pressure inside a closed container when an RC electric ducted fan engine produces 8 lb of thrust. The scope includes theoretical considerations of thrust, pressure differentials, and practical applications in a supercharger design.
Participants do not reach a consensus on the exact pressure calculation, as the discussion includes varying assumptions about the container size and the nature of the airflow. Multiple views on the relationship between thrust and pressure remain present.
Assumptions about the container's dimensions, the nature of the airflow, and the specific configuration of the ducted fan are not fully resolved, which may affect the pressure calculations.
Your statement implies that there's a net pressure differential between the contaniner and the outside air that results in 8 lbs of force at the fan. Also, there's no blowing, the ducted fan is acting as a compressor if it's output is going into a closed container. The pressure would be 8 lbs divided by the cross sectional area of the duct containing the fan. If the duct has a diameter of 4 inches, then the area of the duct is pi x r^2 = pi x (2)^2 = 12.566 in^2. Pressure would be 8 lbs / 12.566 in^2 ~= .636 psi.Subaru_STI said:If I have a RC electric ducted fan engine blowing at 8 lb of thrust into a closed container, what PSI would it be inside of the container, (when the engine is runny continuously)?