What rate is x^4 increasing when x=4?

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The discussion focuses on determining the rate of increase of the function x^4 when x equals 4, given that x is increasing at a rate of 2 units per second. The derivative dx(t)/dt is specified as 2, and x(t) is set to 4. The application of the chain rule in calculus is emphasized as a necessary step to solve the problem accurately.

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If x is positive and increasing at a rate of 2 units per second, at what rate is x^4 increasing when x=4?

I don't even know how to start.
If you can help me I would be greatful.
 
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If x is increasing at the rate of 2 units/second then it must be increasing wrt some variable, call it t. So you are given dx(t)/dt=2 and x(t)=4. Now take the derivative of x(t)^4 and don't forget the chain rule.
 
duh stupid me I know what to do thank you anyway
 

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