Given: cos(x)(adsbygoogle = window.adsbygoogle || []).push({}); ^{[itex]\frac{1}{x}[/itex]}

Find [itex]\frac{dy}{dx}[/itex]:

Now I know... [itex]\frac{dy}{dx}[/itex] of cos(x) = -sin(x)

and [itex]\frac{dy}{dx}[/itex] of [itex]\frac{1}{x}[/itex]= [itex]\frac{-1}{x^2}[/itex]

But I am unsure what formula to apply, and where to go from here?

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# What to use and how to best do it?

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