- #1

- 4

- 0

My equation to solve is (xy+(x^2))dx + (-1)dy=0

For method of exact solutions, the partials are not equal to each other so I cannot use

exact solutions (reverse chain rule)

I dont know how to solve this

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- Thread starter highc1157
- Start date

- #1

- 4

- 0

My equation to solve is (xy+(x^2))dx + (-1)dy=0

For method of exact solutions, the partials are not equal to each other so I cannot use

exact solutions (reverse chain rule)

I dont know how to solve this

- #2

lurflurf

Homework Helper

- 2,440

- 138

Any equation is exact in some coordinates so find them.

you stated (correctly)

(xy+x

is not zero but we can use the fact that

(((xy+x

to conclude that the equation is exact in

∫((xy+x

and y since (xy+(x

(-y-sqrt(-2(-x

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