What Torque is Needed for a Hydraulic Motor to Lift a 10 lb Box 20 Feet?

AI Thread Summary
To lift a 10 lb box 20 feet using a hydraulic motor, the required torque can be calculated using a 6-inch diameter sprocket, resulting in 30 inch-pounds or 2.5 foot-pounds. The weight of the chain adds an additional 25 lbs, which must also be considered in the torque calculations. The discussion highlights the need for a diagram to clarify the mechanics of the setup, particularly regarding the chain anchors. Participants noted that the scenario described may not be realistic, leading to a suggestion of using a 12VDC motor instead of a hydraulic one for cost-effectiveness. The conversation emphasizes the importance of accurate calculations and understanding the system's dynamics.
dakotahm88
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TL;DR Summary
Sprocket question
Need some help.
Trying to lift a 10 lb box 20 feet.
Hydraulic motor driven.
Bucket attached to chain anchors on each end of the chain.
6” diameter sprocket on top and bottom, the bottom sprocket will be driven by a hydraulic motor.

How much torque does the hydraulic motor need? Weight of chain let’s say is 25 lbs for this example. Disregard friction.
 
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dakotahm88 said:
TL;DR Summary: Sprocket question

Need some help.
Trying to lift a 10 lb box 20 feet.
Hydraulic motor driven.
Bucket attached to chain anchors on each end of the chain.
6” diameter sprocket on top and bottom, the bottom sprocket will be driven by a hydraulic motor.

How much torque does the hydraulic motor need? Weight of chain let’s say is 25 lbs for this example. Disregard friction.
Forgot to add, let’s say we’re moving 1 foot per second.
 
Could you attach a 10-lb weight at the opposite side of the loop, as a counter-weight?
 
Not in this particular scenario
 
The ships anchors, attached to both ends of the chain, will prevent the chain from moving. The hydrostatic pressure of the water, will be insufficient to drive the hydraulic motor, up the chain.
Maybe a diagram would help.
 
dakotahm88 said:
How much torque does the hydraulic motor need?
6" diameter = 3" radius ; 10 lb force.
Torque = 3" * 10 lb = 30 inch⋅pound = 2.5 ft⋅lb .

3" radius = 0.0762 m
10 lb = 4.536 kg
Force = 4.536 * 9.8 = 44.45 newton.
0.0762 * 44.45 = 3.387 N⋅m
 
Baluncore said:
The ships anchors, attached to both ends of the chain, will prevent the chain from moving.
I can't picture this on a "ship". One anchor up and one anchor down is not a useful scenario and wouldn't that be the case with one anchor at each end of a chain?
We do need a diagram because, in my mind, the two sides of the chain loop would balance.
 
Do you now know the answer, or what question you should have asked, and what information is required?
 
  • #10
yes I was calculating everything correctly, just didn’t seem realistic. I’m going to give it a go. I’ll post results! Probably going to use a 12VDC motor instead of hydraulic. Much cheaper to assemble.
 
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