What Value of k Ensures Consistency in These Simultaneous Equations?

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SUMMARY

The simultaneous equations 6x - 7y + 2z = 4, 6x - y - z = 7, and 2x - 3y + z = k are consistent only when k = 1. The determinant of the coefficient matrix is -9, indicating that the equations are independent. To analyze the system, one should set up the augmented matrix and apply row operations to achieve row reduced echelon form, which clarifies the conditions for consistency.

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Homework Statement



Show that the simultanbeous equations

[itex]6x-7y+2z=4[/itex]

[itex]6x-y-z=7[/itex]

[itex]2x-3y+z=k[/itex]

where k is a constant, are consisten only when k=1.


The Attempt at a Solution



Don't know how to start, the determinent of the co-efficient matrix is -9. This means they are independent, which means I can't express multiples of (1) and (2) for (3) right? I tried to get x and y in terms of z, then substitute for (3)... Doesn't work. I need the method.
 
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Set up the augmented matrix of your system of equations (since the order in which the equations are given is unimportant, you can set things up this way)

[tex] \begin{pmatrix}<br /> 2 & -3 & \hphantom{-}1 & k \\<br /> 6 & -7 & \hphantom{-}2 & 4\\<br /> 6 & -1 & -1 & 7<br /> \end{pmatrix}[/tex]


Use row operations to reduce this to row reduced echelon form. You'll see why when you reach that form.
 

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