- #1
andreynr6
- 1
- 0
Excuse me for my english;
Decide for all the x so this works out; ((2x-7)/(x3+3))<(9/x)<=x²-5x+9
where "<=" is the same as "and =".
Having some troubles getting the right values between (9/x)<=x²-5x+9, but otherwise it's fine..
hope you can help me!
Decide for all the x so this works out; ((2x-7)/(x3+3))<(9/x)<=x²-5x+9
where "<=" is the same as "and =".
Having some troubles getting the right values between (9/x)<=x²-5x+9, but otherwise it's fine..
hope you can help me!