What Voltage Does a Bird Feel on a Power Line?

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Homework Help Overview

The problem involves a bird standing on an electric transmission line and seeks to determine the voltage the bird feels due to the current flowing through the line. The context includes concepts of electrical resistance and potential difference.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to find the voltage difference between the bird's feet, considering the resistance of the wire and the current. Some suggest treating the section of wire as a resistor, while others question the relevance of the bird's properties in the calculation.

Discussion Status

There is an ongoing exploration of how to calculate the voltage drop over the distance between the bird's feet. Some participants have provided guidance on focusing on the wire's properties rather than the bird itself. Questions about the inclusion of a factor of two in the voltage loss equation indicate a divergence in understanding.

Contextual Notes

Participants note that specific information about the bird's resistance is not provided, and there is some confusion regarding the application of the voltage loss formula in this context.

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Homework Statement


A bird stands on an electric transmission line carrying 2210 A, as seen in the figure below. The line has 3.32E-5 Ω resistance per meter and the bird's feet are 3.80 cm apart. What voltage does the bird feel?


Homework Equations



R=sigma(L)/A
I=V/R

The Attempt at a Solution


I wanted to solve for V of the bird, but neither the resistance of the bird nor the area of the bird is given. Help?
 

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You are trying to find the voltage difference between the two points on the wire.
Think of the section of wire as a resistor
 
You are asked to find the potential difference between the birds legs. You do not need to know anything about the bird to find this. Your are given a resistivity, a distance and a current. Find the voltage.
 
I think you are being asked to calculate the difference in potential (voltage) between the bird's feet. Just leave the bird out of it and calculate the voltage drop over 3.8 cm of transmission line.

Edit: Oops! Upstaged TWICE
 
Ok so I got it by using voltage loss=amps*wire resitance/meter*distance
Usually this equation is
voltage loss=amps*wire resitance/meter*distance*2 wires
Why was it not necessary to multiply the answer by 2 in this case?
 
Where did the 2 come from ?
 
I thought that was the equation for voltage loss. Is it not?
 
Is the "2" perhaps included in that to calculate the voltage loss over a 2-conductor cable, like a lamp-cord?
 

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