What Voltage Is Needed to Charge a 7.0 µF Capacitor with 7.50 x 10^-5 C?

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SUMMARY

The voltage required to charge a 7.0 µF capacitor with a charge of 7.50 x 10^-5 C is calculated using the formula V = q/C. By substituting the values, V = (7.50 x 10^-5 C) / (7.0 x 10^-6 F), which simplifies to V = 10.71 V. It is essential to convert the capacitance from microfarads to farads for accurate calculations, as 1 µF equals 10^-6 F.

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  • Basic algebra skills for manipulating equations
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Homework Statement



What voltage is required to store 7.50 x 10-5 C of charge on the plates of a 7.0 µF capacitor?

i believe the equation to be: q = CV

so V = q/C

i've tried plugging in the numbers to this equation and don't get the correct answer. is 7.0 uF need to be converted to a more compatible number?

thankyou.

Homework Equations





The Attempt at a Solution

 
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Yes, you need to work in one set of units, making any conversions that are necessary, and you need to do the right things with numeric prefixes like "micro" = 10^-6.

Write out your equation again for us, this time including the units and prefix multiplications, and we'll see where you are.
 

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