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Alice7979
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Homework Statement
A capacitor stores 7.9 x 10-2 C of charge when connected to a 6.0-V battery. How much charge does the capacitor store when connected to a 9.0-V battery?
Homework Equations
PE=CQ/2
The Attempt at a Solution
QV^2=CQ^2
(7.9 x 10-2)(6)/2 = Q(9)
C= .05 C