Capacitors: find he charge for the new battery

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Alice7979
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Homework Statement


A capacitor stores 7.9 x 10-2 C of charge when connected to a 6.0-V battery. How much charge does the capacitor store when connected to a 9.0-V battery?

Homework Equations


PE=CQ/2

The Attempt at a Solution


QV^2=CQ^2
(7.9 x 10-2)(6)/2 = Q(9)
C= .05 C
 
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You are looking for an equation that relates capacitance, charge held on the plates, and the voltage across the plates.
1. Solve for capacitance.
2. Rearrange the equation and solve for charge.
 
I guess I made that more complicated
 
If you want to post the answer you came up with, I will see if it matches mine.
 
.1185 C
 
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That's what I got. The precision of the given data is 2 significant figures, so I rounded to 0.12 C.
 
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