What Wavelength Maximizes u(lambda) for a 50,000 K Star?

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 4K views
platonic
Messages
38
Reaction score
0

Homework Statement


At what wavelength is u(lambda) a maximum for a star with a surface temperature of 50,000 K?


Homework Equations


Planck's law
u(lambda)=8(pi)hc/(lambda^5*(e^(hc/kTlambda)-1)

The Attempt at a Solution


I think the maximum is where the derivative of the function u(lambda)=0, but the derivative is too messy to solve in terms of lambda so I can't find the wavelength. So I think I'm way off as far as how to solve it. Any help would be appreciated.
 
Physics news on Phys.org
well, the differentiation should be done in order to get \lambda at maximum energy density. The differentiation isn't too hard, try using the product rule first.