What would the slope of the force between 2 charged particles vs 1/r^2 give me?

Thread starter dannolul
Start date Apr 30, 2024
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Force Inverse Slope

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The discussion revolves around understanding the slope of a graph depicting the force between two charged particles as a function of distance, specifically in relation to the inverse square law (1/r^2). Participants seek clarification on what to plot on the y-axis and x-axis, along with their respective units. The gradient of the plot, defined as Δy/Δx, raises questions about how to determine the units for the slope in this context. Understanding these units is crucial for interpreting the physical significance of the slope. Clear definitions of the axes and their units are essential for accurate analysis.

Apr 30, 2024

dannolul

Homework Statement: A lab was performed by taking 2 charged particles at varying distances and measuring the force between them. (Dry data, and a graph of Fe vs 1/r^2 have been given.) Assume the charges are equal of magnitude. using the slope of the line and the value of coulomb's constant constant, calculate for the charge on one particle

Relevant Equations: Fe=(kq1q2)/(r^2)

I can get the slope of the line, but then I dont know what the slope is (units or whatever it is) then i get lost from there.

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May 1, 2024

Ibix

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What did you plot on the ##y## axis and in what units? What did you plot on the ##x## axis and in what units? If the gradient of a ##y##-versus-##x## plot is ##\Delta y/\Delta x## then can you determine the units in this case?

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