A formula for finding the normal vector for curvature is:(adsbygoogle = window.adsbygoogle || []).push({});

N=(dT/ds)/(||dT/ds||)

Where

dT=change in tangent vector

ds=change in distance travelled

Another fromula was:

N=(dT/dt)/(||dT/dt||)

What's dt ?

Is it the same as ds? I don't think so cause the course notes said that calculations can be done more easily using the second formula.

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# What's dt in finding normal vector for curvature

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