What's Incorrect About Calculating Impulse in This Volleyball Spike Example?

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Homework Help Overview

The discussion revolves around calculating impulse in the context of a volleyball spike. The problem involves a ball with a specified mass and speeds before and after being spiked, prompting questions about the correct approach to calculating impulse while considering vector directions.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the calculation of impulse, questioning the treatment of momentum as vectors and the necessity of considering direction in the subtraction process. There are attempts to clarify how to represent the vectors and their components.

Discussion Status

The discussion is active, with participants seeking clarification on vector subtraction and the implications of treating momentum as vectors. Some guidance has been provided regarding the representation of momentum in component form and the process of vector subtraction.

Contextual Notes

Participants express uncertainty about the vector nature of impulse and momentum, indicating a need for further exploration of these concepts. There is a focus on the initial and final momentum values and their respective directions.

Ion1776
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What wrong with this problem?

A ball is traveling horizontally over a volleyball net when a player "spikes" it, driving it straight down to the ground. The ball's mass is 0.24 kg, its speed before being hit is 6.4 m/s and its speed immediately after the spike is 21 m/s. What is the magnitude of the impulse from the spike?

J=(.24kg)(21m/s)-(.24kg)(6.4m/s)=3.5

this is wrong, what's wrong
 
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Still need some input on this please?
 


Ion1776 said:
J=(.24kg)(21m/s)-(.24kg)(6.4m/s)=3.5

this is wrong, what's wrong
Impulse and momentum are vectors--you must take direction into account. Subtract them as vectors, not just numbers.
 


This probably sounds stupid but what do u mean by subtract them as vectors.

I know know what vectors are but...
 


Ion1776 said:
This probably sounds stupid but what do u mean by subtract them as vectors.

I know know what vectors are but...
You just subtracted them as numbers--which means you treated them as if they pointed in the same direction.

To subtract vectors, draw yourself a diagram. The two vectors are perpendicular to each other. Or you can find their components and subtract them.

Hint: Subtracting is the inverse of adding. How would you add two perpendicular vectors?
 


again this sounds dumb, but would add these as vectors give you

(.48kg, 27.4m/s)
 


Ion1776 said:
again this sounds dumb, but would add these as vectors give you

(.48kg, 27.4m/s)
No, that doesn't quite make sense.

I'll start you off. Let's call horizontal and vertical the x and y axes (like usual).

The initial momentum is:
mv = (.24 kg)*(6.4 m/s) = 1.54 kg-m/s in the + x direction
Expressed as a vector using components, it would be:
(1.54, 0)

The final momentum is
mv = (.24 kg)*(21 m/s) = 5.04 kg-m/s in the - y direction
Expressed as a vector using components, it would be:
(0, -5.04)

Now subtract those two momentum vectors and find the magnitude of the impulse.
 


Alright got it
 

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