Whats the force applied for a cart traveling up a hill?

1. Feb 28, 2016

AndroidX7

1. The problem statement, all variables and given/known data

A cart travels up a hill at a constant velocity in 2.5 (s). What power is developed by the cart?
m=120 kg
meters=12m
θ=21°
2. Relevant equations

P=w/t
w=F(parallel)×meters×cosθ
3. The attempt at a solution
P= w/t= Fdcosθ/2.5= F(12)(.93)/2.5= 11,2F/2.5= 4.5F
How do I find F?

2. Feb 28, 2016

Qwertywerty

Tip : Using the formula P=FIIv would be an easier approach(Why?)

The why also tells you the method of finding F.

Hint : What forces act on the car?
What is an object's acceleration when it travels with uniform velocity?

Hope this helps,
Qwertywerty.

3. Feb 28, 2016

AndroidX7

The problem I'm thinking is that F= ma and so without acceleration, how is there Force?
Is something just flying past me here?

4. Feb 28, 2016

AndroidX7

Wait. I just got it.
F=0 therefore P=0.
I think I just wasn't expecting a trick question.

5. Feb 28, 2016

Qwertywerty

We typically say Fnet=ma. Thus, the correct conclusion to be drawn is..?

6. Feb 28, 2016

Qwertywerty

I'm afraid that's wrong;)

7. Feb 28, 2016

AndroidX7

If I'm not mistaken "net" means Σ correct?

8. Feb 28, 2016

Qwertywerty

Yes. So what forces, or components of forces, are acting on the car, along the incline?

9. Feb 28, 2016

AndroidX7

F normal
F gravity
F applied

10. Feb 28, 2016

Qwertywerty

Out of these, which forces affect the car along the incline?

Hint : If you can figure out F applied somehow, you would be able to find the power developed using the formula P=F.v

11. Feb 28, 2016

AndroidX7

Well I know that n and g (although now that I think about it it might be g and θ) combine to find the minimal force you need to overcome gravity and inversely shows Fa, but I don't think I know how that'd work.

12. Feb 28, 2016

Qwertywerty

Hmm..I'm gonna try squeezing in a bit more. Do you know how to draw a free-body diagram? If you do, draw one for the car.

Now, draw the components along the incline. The net force along the incline must be zero, as we have seen earlier. Consider mg to be the force of gravity and a random variable , say F, for force exerted by the car. You will see that that F is independent of the normal.

Can you find out the relation between mg and F, using all that has been mentioned so far?

13. Feb 28, 2016

Qwertywerty

I'd also reccomend you reading more theory related to this stuff.

14. Feb 28, 2016

AndroidX7

By this I'm assuming that F= mg,
but according to my notes, as far as I can gather, F normal must equal Fa due to gravity, but your saying it's independent.

15. Feb 28, 2016

AndroidX7

where?

16. Feb 28, 2016

Qwertywerty

As I said at the start of my post, you will need to make use of a free-body diagram - your assumption is, unfortunately, wrong.

Also, I said force that the car exerts is independent of the normal. Normal force is related to gravity, but that is not relevant here. As I said earlier, you need to construct a diagram to understand what's going on.

17. Feb 28, 2016

Qwertywerty

I will not be able to help you there. You should post this question in the Science Education's textbooks forum, or something similar.

18. Feb 28, 2016

Qwertywerty

Edit.

19. Feb 28, 2016

AndroidX7

So then there's no relevant relation between mg and Fn.
Because i was hoping cos21 may subtract from mg to acquire Fn.

Attached Files:

• 20160228_233122.jpg
File size:
33.4 KB
Views:
31
20. Feb 28, 2016

Qwertywerty

-In this question. I hope I've cleared that satisfactorily.

You've gotten the basic diagram correct. Take components of the forces along the incline.