Jason Wang
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Will anyone give me an explanation helping me understanding it?
The recoil energy in an optical lattice is defined by the formula E = p²/(2m), where p = h/λ represents the momentum of a lattice photon and m is the mass of the atom or ion trapped in the lattice. This energy quantifies the kinetic energy an atom or ion would possess after emitting a photon while initially at rest. Key variables include M (mass of the emitting particle), v (recoil velocity), Ep (energy of the emitted photons), c (speed of light in vacuum), and k (wave vector).
PREREQUISITESPhysicists, optical lattice researchers, and students studying quantum mechanics or atomic physics will benefit from this discussion.
Redbelly98 said:Welcome to Physics Forums.
The recoil energy is p2/2m, where p=h/λ is the momentum of a lattice photon and m is the mass of an atom or ion trapped in the lattice.
The recoil energy is the kinetic energy an atom (or ion) would have after emitting a photon, if initially at rest.
Rajini said:Hi,
Recoil energy E=Mv2/2=p2/(2M)=Ep2/(2Mc2)=(\hbark)2/(2M).
M=mass of something (nucleus, atom, ion, etc), which emits photons.
v=recoil velocity due to emission of photons.
p=momentum.
Ep= Energy of the emitted photons.
c=velocity of light in vacuum.
k=wave vector.