What's the relation between angular resolution and distance

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The discussion focuses on calculating the angular resolution of a telescope and its application to imaging the moon. The formula θ=1.22λ/D is used to determine angular resolution, resulting in a value of 4.88x10^-7 radians. The user seeks to understand how angular resolution relates to the distance between distinguishable objects on the moon. It is clarified that angular resolution cannot be directly converted to meters; instead, the angular separation must be calculated based on the distance from Earth to the moon. Understanding this relationship is crucial for determining the minimum distance between two objects that can be resolved by the telescope.
Cocoleia
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Homework Statement


At first I needed to calculate the angular resolution of a telescope (diameter 1m, for visible light) so I used θ=1.22λ/D and got 4.88x10^-7 rad. Now I am asked: "If we wished to use this telescope to image the moon, what is the closest distance two objects can be to be distinguished by such a telescope?"
I don't understand what the relationship between angular resolution and distance is.

Homework Equations



θ=1.22λ/D
 
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Cocoleia said:
Is it just a matter of converting my answer to meters?
You cannot "convert" radians to metres.
If two points on the moon are distance x apart, what is their angular separation when viewed from Earth?
 
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