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Understanding Tension in a Hanging Chain on a Fixed Sphere - Homework Help
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[QUOTE="mooncrater, post: 5012386, member: 517388"] [h2]Homework Statement [/h2]The question says A chain of mass per unit length k and length 1.5 m rest on a fixed smooth sphere of radius R= 2/π m . Tension in the thread is asked.The question figure is attached.[h2]Homework Equations[/h2] N/a[h2]The Attempt at a Solution[/h2] [ATTACH=full]79196[/ATTACH] [ATTACH=full]79196[/ATTACH] I think that the tension has to balance two types of forces : 1) rightward force of part AC(touching) 2)downward force of part CB(hanging) Finding first type of force: Using Fbd(attached) of small part taken in touching part Then Ncos(theta)=(dm)g → N=(dm)g/cos(th.)...(1) Length of that part =R(d(th.)) mass of that small part =Rk(d(th.)) Using Fbd rightward force on the small part =Nsin(th.)=(dm)g(tan(th.)) =Rkgtan(th.)(d(th.)) Now if I want to integrate it , i would have to use limits from 0 to π/2 BUT tan (th.) is not integrable b/w 0 to π/2 . So what's wrong with my answer ? [/QUOTE]
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Understanding Tension in a Hanging Chain on a Fixed Sphere - Homework Help
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