Wheatstone bridge arrangement with an ideal wire in middle

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SUMMARY

The discussion focuses on analyzing a Wheatstone bridge arrangement with resistances A (20 ohms), B (15 ohms), C (5 ohms), and D (10 ohms) connected to a 2V battery. Participants clarify that the connecting wire has zero resistance, leading to confusion about infinite current. The correct approach involves treating the circuit as a combination of resistors in parallel and series to determine the current through each resistor, ultimately leading to the current through the connecting wire. The effective resistance calculations yield a total of 10 ohms, resulting in a current draw of 0.2 amperes from the source.

PREREQUISITES
  • Understanding of Ohm's Law (V=IR)
  • Knowledge of series and parallel resistor combinations
  • Familiarity with circuit analysis techniques
  • Basic concepts of electrical resistance
NEXT STEPS
  • Calculate the current through each resistor in a Wheatstone bridge configuration
  • Learn about effective resistance in series and parallel circuits
  • Explore the implications of ideal wires in electrical circuits
  • Study advanced circuit analysis techniques using Kirchhoff's laws
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Students preparing for physics entrance exams, electrical engineering students, and anyone interested in circuit analysis and resistor configurations.

_RisH_
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Homework Statement


I came across this questions in one of the online entrance tests,so i do not remember the exact values,I remembered the arrangement.
________________
|... |...|
|... A...C
2v...|--------| (Please ignore the dots,they are to prevent figure from getting
|....B...D distorted)
|________|_______|

A,B,C,D are resistances connected to a 2v battery.Rest everything are ideal wires.We have to find the current through the connecting wire(-----).

Let A-20ohms,B-15ohm,C-5ohms,D-10ohms



Homework Equations



V=I*R

The Attempt at a Solution



The current flowing in ---- wire will be the difference in potential across it divided by the resistance.But since it is ideal it has 0 resistance which gives infinite current.I am totally confused.(The answer is a finite value.)
 
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Forget about the bridge, just concentrate on determining the current in each resistor, first. Obviously, resistors A and C are in parallel?
 
Yes...but ignoring the bridge would mean (AseriesB)||(C series D) ri8?
 
_RisH_ said:
Yes...but ignoring the bridge would mean (AseriesB)||(C series D) ri8?

No. It would mean (A parallel C) in series with (B parallel D). Calculate the current through the resistors and from this you can find the current through the bridge.
 
_RisH_ said:
Yes...but ignoring the bridge would mean (AseriesB)||(C series D) ri8?

I'm not saying ignore anything, nor suggesting any alterations to the circuit. I'm suggesting that you not get hung up on it being any special arrangement or having any special name. Just analyse it as a 4 resistor circuit to determine the current in each of the 4 resistors. The connecting wire remains in place right where it is.

Your first step could be to determine the current drawn from the source, once you have calculated the effective resistance of that bunch.

Then we'll take a closer look ...
 
A||C-4ohms B||D-6 ohms. Equiv. resis.=10 ohms.So current drawn is .2 ampere.Is this correct?
 
_RisH_ said:
A||C-4ohms B||D-6 ohms. Equiv. resis.=10 ohms.So current drawn is .2 ampere.Is this correct?

Correct.Now find the current through C & D (or A & B) and hence you will get the current through the connecting wire.
 

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