Resistance Of A Unbalanced Wheatstone Bridge Circuit

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Homework Help Overview

The discussion revolves around determining the equivalent resistance of an unbalanced Wheatstone Bridge circuit, specifically when the galvanometer current is not zero. Participants are exploring the implications of this unbalanced condition on circuit analysis.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are considering how to calculate the equivalent resistance, with some suggesting the need to account for the galvanometer's resistance. Others question the relevance of the galvanometer in the analysis, proposing to simplify the circuit by replacing it with a simple resistance.

Discussion Status

The discussion is active, with participants offering various perspectives on how to approach the problem. Some guidance has been provided regarding the use of Kirchhoff's rules and symbolic solutions, but there is no explicit consensus on the best method to proceed.

Contextual Notes

There is an indication that the original problem may differ from standard textbook examples, as participants note the complexity introduced by the galvanometer and express a desire to focus on the circuit itself. Additionally, some participants mention constraints related to the information available, such as only having resistance values without current or emf data.

AbhiFromXtraZ
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Resistance Of An Unbalanced Wheatstone Bridge Circuit

How to find the equivalent resistance across the battery (I mean the whole circuit) of a Wheatstone Bridge circuit IF GALVANOMETER CURRENT IS NOT ZERO (i.e. unbalanced circuit)?
 
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AbhiFromXtraZ said:
How to find the equivalent resistance across the battery (I mean the whole circuit) of a Wheatstone Bridge circuit IF GALVANOMETER CURRENT IS NOT ZERO (i.e. unbalanced circuit)?

I presume 'find' means calculate. You need to know the resistance of the galvanometer. (Note that the 'resistance of the galvanometer' may not mean acutally the resistance of the instrument but might be that of the low resistor that is often included in 'shunt' (in parallel) with it. But that's the one you need to know.)

I thought, I may be wrong, they often put a high resistor in series with the instrument. In both cases it takes a low current. But in the second case this current through the galvo is something small in a way you can ignore - your circuit would be like two parallel branches each consisting of two resistors in series.

If nothing is known of the resistance you will just have to call it Rg or something and develop the equations algebraically. Get expressions for all the currents and voltages, put them together for a solution which will be an expression containing Rg. If you get stuck consult your textbook - it is an absolutely standard kind of problem - or else come back here showing what you have done.
 
My book's problem is for balanced bridge...And my question is for unbalanced...you just made it complex with galvo...for convenience please replace the galvo with a simple resistance...galvo is not important...circuit is important...and nothing has to be changed here...
 
You have a circuit shown in the figure. Using Kirchhoff's rules, determine the current Is flowing out from the voltage source. The emf of the source is E.

ehild
 

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Oh Thanks ehild..I will try..
 
You mean I need current and emf?...But I have only the resistances...how can I do?
 
Solve symbolically, with emf E. Find the current Is across the battery in terms of E. The equivalent resistance is Req=E/Is.

You can also apply delta-star conversion to get the equivalent resistance. http://www.electrical4u.com/delta-star-transformation-star-delta-transformation/

ehild
 

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