Wheatstone bridge arrangement with an ideal wire in middle

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Homework Help Overview

The discussion revolves around a Wheatstone bridge arrangement involving resistors A, B, C, and D connected to a 2V battery, with a focus on determining the current through an ideal connecting wire. The original poster expresses confusion regarding the calculation of current due to the ideal nature of the wire.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the configuration of the resistors and question how to analyze the circuit without focusing on the bridge aspect. There is discussion about calculating the current through each resistor and the effective resistance of the circuit.

Discussion Status

Some participants have provided guidance on analyzing the circuit as a standard four-resistor setup. The original poster has calculated the equivalent resistances and the current drawn from the source, leading to further inquiries about the current through specific resistors.

Contextual Notes

The original poster notes a lack of exact values from the problem statement and expresses confusion about the implications of the ideal wire on current calculations.

_RisH_
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Homework Statement


I came across this questions in one of the online entrance tests,so i do not remember the exact values,I remembered the arrangement.
________________
|... |...|
|... A...C
2v...|--------| (Please ignore the dots,they are to prevent figure from getting
|....B...D distorted)
|________|_______|

A,B,C,D are resistances connected to a 2v battery.Rest everything are ideal wires.We have to find the current through the connecting wire(-----).

Let A-20ohms,B-15ohm,C-5ohms,D-10ohms



Homework Equations



V=I*R

The Attempt at a Solution



The current flowing in ---- wire will be the difference in potential across it divided by the resistance.But since it is ideal it has 0 resistance which gives infinite current.I am totally confused.(The answer is a finite value.)
 
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Forget about the bridge, just concentrate on determining the current in each resistor, first. Obviously, resistors A and C are in parallel?
 
Yes...but ignoring the bridge would mean (AseriesB)||(C series D) ri8?
 
_RisH_ said:
Yes...but ignoring the bridge would mean (AseriesB)||(C series D) ri8?

No. It would mean (A parallel C) in series with (B parallel D). Calculate the current through the resistors and from this you can find the current through the bridge.
 
_RisH_ said:
Yes...but ignoring the bridge would mean (AseriesB)||(C series D) ri8?

I'm not saying ignore anything, nor suggesting any alterations to the circuit. I'm suggesting that you not get hung up on it being any special arrangement or having any special name. Just analyse it as a 4 resistor circuit to determine the current in each of the 4 resistors. The connecting wire remains in place right where it is.

Your first step could be to determine the current drawn from the source, once you have calculated the effective resistance of that bunch.

Then we'll take a closer look ...
 
A||C-4ohms B||D-6 ohms. Equiv. resis.=10 ohms.So current drawn is .2 ampere.Is this correct?
 
_RisH_ said:
A||C-4ohms B||D-6 ohms. Equiv. resis.=10 ohms.So current drawn is .2 ampere.Is this correct?

Correct.Now find the current through C & D (or A & B) and hence you will get the current through the connecting wire.
 

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