Wheel Rotated By Force on String.

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Homework Help Overview

The problem involves a heavy wheel with a rope spooled around it, where a woman pulls the rope to accelerate the wheel from rest to a specified angular speed over a given time. The discussion focuses on determining the linear speed of the rope, the average force exerted by the woman, and the work done on the wheel.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between angular and linear speed, with one attempting to calculate the final linear speed of the rope. There is also an exploration of the equations relating force, torque, and angular acceleration, with some questioning the appropriateness of the formulas used. The concept of work done is raised, with a suggestion to consider kinetic energy in the context of the problem.

Discussion Status

Some participants have provided guidance on the equations and concepts involved, particularly regarding the relationship between torque and kinetic energy. Multiple interpretations of the approach to calculating work and force are being explored, indicating a productive discussion without explicit consensus.

Contextual Notes

Participants are working under the assumption that friction can be ignored and are interpreting the problem's requirements for calculating force and work based on the given parameters.

Zebulinn
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Homework Statement


A heavy wheel (radius = 0.3 meters, mass = 12 kg) has a rope spooled around it. A woman
pulls on the rope from below with a constant force. She is able to bring the wheel from
rest up to 1 radian per second in 10 seconds.
[Ignore friction in the hub of the wheel.]
a) When the wheel is at its final speed, at what linear speed v is the rope unspooling?
b) How much (average) force was exerted by the woman?
c) How much work was done on the wheel by the woman?


Homework Equations





The Attempt at a Solution


For a) I used (2*R*pi)/2*pi and got .3 m/s for the final linear speed of the rope.

For b) I started with .5*M*R(alpha)=RT with alpha=a/R to get .5*M*a=T with T being the force of tension which would be the force exerted by the woman? I must be using the wrong formula or something here.

would c) be the force times the length of string unspooled?
 
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b) seems fine
c) rather use EK = 1/2 ω2 that is the work done by the torque is equal to the change in kinetic energy of the wheel.
 
Zebulinn said:
For b) I started with .5*M*R(alpha)=RT with alpha=a/R to get .5*M*a=T
.5*M*R2α=RT, but the next equation is right, so maybe that was an error in writing the post.
would c) be the force times the length of string unspooled?
Yes. You could use Basic_Physics' method (but it's EK = 1/2 I ω2 = 1/4 MR2 ω2), but seems to me the question is leading you towards force x distance.
 
Thanks. What does EK stand for? The kinetic energy?
 
Zebulinn said:
Thanks. What does EK stand for? The kinetic energy?
Yes, I assumed that's what BasicPhysics intended. I just copied that notation.
 

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