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## Homework Statement

A wheelbarrow has a mass of 35.0 kg without the wheel. When empty, the center of mass is 0.400 m from the axle. A load with a mass of 55.0 kg is put in the wheelbarrow, 0.600 m from the axle. Ophelia holds the handles of the wheelbarrow, 1.20 m from the axle. She lifts the handles so that they make a 25.0° angle with the ground. What is the upward force that Ophelia applies to the handles in order to hold the wheelbarrow in that position?

## Homework Equations

[tex]\Sigma[/tex]Fx=0

[tex]\Sigma[/tex]Fy=0

Torque=rFsin[tex]\vartheta[/tex]

## The Attempt at a Solution

[tex]\Sigma[/tex]Fx=0 I figure there's nothing to find out here because it's fairly obvious...I think.

[tex]\Sigma[/tex]Fy=0

Here, I figure it's mg=Fnormal + Fophelia

and since Ophelia is applying a torque force around the wheel:

mg=Fnormal + rFosin[tex]\theta[/tex]

Some problems: I don't know how to solve for Fo since Fnormal is in there too and is unknown, and I don't know how the difference in xcm should come in other than choosing axis of origin (of which I chose the wheel)