# Wheelbarrow in Static equilibrium

## Homework Statement

A wheelbarrow has a mass of 35.0 kg without the wheel. When empty, the center of mass is 0.400 m from the axle. A load with a mass of 55.0 kg is put in the wheelbarrow, 0.600 m from the axle. Ophelia holds the handles of the wheelbarrow, 1.20 m from the axle. She lifts the handles so that they make a 25.0° angle with the ground. What is the upward force that Ophelia applies to the handles in order to hold the wheelbarrow in that position?

## Homework Equations

$$\Sigma$$Fx=0
$$\Sigma$$Fy=0
Torque=rFsin$$\vartheta$$

## The Attempt at a Solution

$$\Sigma$$Fx=0 I figure there's nothing to find out here because it's fairly obvious...I think.

$$\Sigma$$Fy=0

Here, I figure it's mg=Fnormal + Fophelia
and since Ophelia is applying a torque force around the wheel:
mg=Fnormal + rFosin$$\theta$$

Some problems: I don't know how to solve for Fo since Fnormal is in there too and is unknown, and I don't know how the difference in xcm should come in other than choosing axis of origin (of which I chose the wheel)