When acceleration depends on the distance

  • Thread starter svkptr
  • Start date

is this possible??

  • yes

    Votes: 1 100.0%
  • no

    Votes: 0 0.0%

  • Total voters
    1
  • #1
1
0

Homework Statement


i am trying to find out velocity at a point of time and distance covered by a particle whose acceleration (a) depends on distance (s). to start with let a = k*s+c were k and c are contants.


Homework Equations


a= k*s+c
we know a=ds/st


The Attempt at a Solution


a=k*s+c

(dv/dt)=k*s+c
or
v=k*s*t+s*t

but i know (s) is not to be treated as conatant... then what to do here?? please help
i cannot frame the differential equation
 

Answers and Replies

  • #2
6,054
391
a = dv/dt = dv/ds ds/dt = dv/ds v
 
  • #3
Dick
Science Advisor
Homework Helper
26,260
619
a(t)=v'(t)=s''(t). So s''(t)=k*s(t)+c. It's a second order ode. Like a harmonic oscillator.
 

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