When acceleration depends on the distance

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SUMMARY

The discussion focuses on determining the velocity of a particle when its acceleration is defined as a function of distance, specifically using the equation a = k*s + c, where k and c are constants. The participant attempts to derive the velocity equation but struggles with treating distance as a variable rather than a constant. The solution involves recognizing that the acceleration leads to a second-order ordinary differential equation (ODE), s''(t) = k*s(t) + c, analogous to a harmonic oscillator.

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  • Understanding of ordinary differential equations (ODEs)
  • Familiarity with concepts of acceleration and velocity in physics
  • Knowledge of harmonic oscillators in mechanics
  • Basic calculus, particularly differentiation
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  • Study the methods for solving second-order ordinary differential equations
  • Explore the characteristics of harmonic oscillators in physics
  • Learn about the relationship between acceleration, velocity, and displacement
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Students in physics or engineering, mathematicians focusing on differential equations, and anyone interested in the dynamics of systems with variable acceleration.

is this possible??

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Homework Statement


i am trying to find out velocity at a point of time and distance covered by a particle whose acceleration (a) depends on distance (s). to start with let a = k*s+c were k and c are contants.


Homework Equations


a= k*s+c
we know a=ds/st


The Attempt at a Solution


a=k*s+c

(dv/dt)=k*s+c
or
v=k*s*t+s*t

but i know (s) is not to be treated as conatant... then what to do here?? please help
i cannot frame the differential equation
 
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a = dv/dt = dv/ds ds/dt = dv/ds v
 
a(t)=v'(t)=s''(t). So s''(t)=k*s(t)+c. It's a second order ode. Like a harmonic oscillator.
 

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