When ave. rate of change = instantaneous rate of change

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SUMMARY

The discussion focuses on finding an interval and a point where the average rate of change (AROC) and the instantaneous rate of change (IROC) are equal for the function f(x) = (x-2) / (x-5). The relevant formulas are AROC = (f(x2) - f(x1)) / (x2 - x1) and IROC = [f(x+h) - f(x)] / h. The Mean Value Theorem is applicable, stating that if f is continuous on [a, b] and differentiable on (a, b), there exists a point c where f'(c) equals the average rate of change over that interval. The function has a vertical asymptote at x = 5, indicating that calculations should be performed within the intervals (-∞, 5) or (5, ∞).

PREREQUISITES
  • Understanding of the Mean Value Theorem
  • Knowledge of calculus concepts: derivatives and rates of change
  • Ability to perform algebraic manipulations
  • Familiarity with graphing functions and identifying asymptotes
NEXT STEPS
  • Study the Mean Value Theorem in detail
  • Practice calculating derivatives for various functions
  • Learn to graph rational functions and identify their asymptotes
  • Explore examples of finding points where AROC equals IROC
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Students studying calculus, particularly those focusing on derivatives and the Mean Value Theorem, as well as educators looking for examples to illustrate these concepts.

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Homework Statement



Given the function f(x)= (x-2) / (x-5), determine an interval and a point where the ave. R.O.C and the instantaneous R.O.C are equal.


Homework Equations



IROC = [ f(x+h) - f(x) ] /h
AROC = f(x2) - f(x1) / x2 - x1

The Attempt at a Solution



I know that in order to satisfy this, the x's must satisfy both equations when using the AROC and IROC formulas.
I'm not sure where to start, though.
I could do guess and check, but I need help for an algebraic method.
 
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DespicableMe said:

Homework Statement



Given the function f(x)= (x-2) / (x-5), determine an interval and a point where the ave. R.O.C and the instantaneous R.O.C are equal.


Homework Equations



IROC = [ f(x+h) - f(x) ] /h
AROC = f(x2) - f(x1) / x2 - x1

The Attempt at a Solution



I know that in order to satisfy this, the x's must satisfy both equations when using the AROC and IROC formulas.
I'm not sure where to start, though.
I could do guess and check, but I need help for an algebraic method.
You might not have seen the Mean Value Theorem yet, but it guarantees that if f is continuous on some interval [a, b], and differentiable on (a, b), then there exists a number c such that f'(c) = (f(b) - f(a))/(b - a).

If you haven't graphed your function, by all means do so. Your function has a vertical asymptote at x = 5, but is continuous everywhere else; i.e., on (-infinity, 5) or (5, infinity). Pick any two numbers that are in the interior of either of these intervals and calculate the average rate of change. Then set f'(x) equal to this number to solve for x.
 

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