When do these two moving particles come together?

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SUMMARY

The discussion revolves around the conditions under which two particles moving along a one-dimensional path collide or do not collide, based on their initial positions, velocities, and accelerations. The first particle starts at x=0 with velocity V1 and acceleration a1, while the second starts at x=L with velocity V2 and acceleration a2. Key insights include the use of the equation x(t) = x0 + vt + 1/2at² to determine collision scenarios, and the importance of analyzing relative velocities and accelerations to predict outcomes. The discussion emphasizes the necessity of understanding quadratic equations and their discriminants to ascertain the existence of real solutions for collision times.

PREREQUISITES
  • Understanding of kinematic equations, specifically x(t) = x0 + vt + 1/2at²
  • Knowledge of quadratic equations and the concept of discriminants
  • Familiarity with relative motion and acceleration concepts
  • Basic graphing skills for visualizing motion scenarios
NEXT STEPS
  • Study the conditions for collision using quadratic equations and discriminants
  • Learn about relative motion and how to analyze it from different reference frames
  • Explore graphing techniques for visualizing particle motion over time
  • Review LaTeX formatting for presenting equations clearly in discussions
USEFUL FOR

Students in physics, particularly those studying kinematics, educators teaching motion concepts, and anyone interested in understanding collision dynamics in one-dimensional motion scenarios.

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Homework Statement
Hello everyone, I have recently joined a physics summer school, for which I have to do homework every day. But I couldn't manage to solve today's problem, so I'm seeking help from you guys.

The question is about two particles moving on a one dimensional path. First one is at x=0 when t=0, and moves with a velocity of V1 and acceleration a1. The other one is at x=L>0 when t=0 and moves with a velocity of V2 and acceleration a2.
Relevant Equations
x(t)=x0+v*t+1/2*a*t^2
Hello everyone, I have recently joined a physics summer school, for which I have to do homework every day. But I couldn't manage to solve today's problem, so I'm seeking help from you guys.

The question is about two particles moving on a one dimensional path. First one is at x=0 when t=0, and moves with a velocity of V1 and acceleration a1. The other one is at x=L>0 when t=0 and moves with a velocity of V2 and acceleration a2. Questions:

In which cases do the objects:
a) not crash
b)crash one time as they go opposite directions
c)crash one time as they go in the same directions
d)crash twice in opposite directions
e)crash twice in same directions
f)crash twice, first traveling in the same direction and then in the opposite direction
g)crash twice, first traveling in the opposite direction and then in the same direction.

Now I understand that it must be x2(t)>x1(t) if they don't crash. I tried solving this inequality but I couldn't eliminate t and my math wasn't good enough for this inequity. I assume I have to find a way to eliminate t to solve further questions as well. So if you can help me I would really appreciate that. Thank you in advance for you help.
 
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Welcome to PF.

You are using the right Relevant Equation, so can you say a few things about the initial velocities and accelerations to result in them crashing going opposite directions versus going the same direction?

Also, in problems like this it is helpful to draw a 2-d graph of the motion of each particle. You can put x on the horizontal axis and time on the vertical axis. Then you can sketch different scenarios with mixes of initial velocities and accelerations to see when you get the 2 particles coming together...

(Also, there is a LaTeX Guide at the bottom of the page -- learning to post equations in LaTeX makes them much more readable) :smile:
 
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berkeman said:
Welcome to PF.

You are using the right Relevant Equation, so can you say a few things about the initial velocities and accelerations to result in them crashing going opposite directions versus going the same direction?

Also, in problems like this it is helpful to draw a 2-d graph of the motion of each particle. You can put x on the horizontal axis and time on the vertical axis. Then you can sketch different scenarios with mixes of initial velocities and accelerations to see when you get the 2 particles coming together...

(Also, there is a LaTeX Guide at the bottom of the page -- learning to post equations in LaTeX makes them much more readable) :smile:
Thank you for your answer, forgive my way of writing the equation, I am new to the site. I actually understand the situations by sketching, and I can give some mathematical statements about them. But for example for the situation where they don't collide, the factor time remains in the inequality and I have no idea how to eliminate it. For the second statement I can say that X1(t)=X2(t), v1+a1*t>0, v2+a2*t<0. But again I don't know how to combine those statements. Do you have any tips for me?
 
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For a) you don't have to solve an inequality. Instead find the condition such that the equation $$X_1(t)=X_2(t)\iff X_1(t)-X_2(t)=0$$ has no real solutions. It would be a quadratic equation, you know when it doesn't have real solutions when the discriminant is less than zero.
 
Yigitu17 said:
I actually understand the situations by sketching
Can you show some of your sketches for each of the situations in the question? If you scan them or take good quality pics of them, you can use the "Attach files" link below the Edit window to upload PDF or JPEG copies of them.

The different scenarios are kind of fun to think about and visualize, actually. I'm not sure yet if they are all possible or not, but most seem just to be related to the signs and magnitudes of the initial velocities and the accelerations. FYI, here are your equations in LaTeX:
$$ x_1(t) = x_{1i} + v_{1}t + \frac{1}{2}a_1t^2 $$
$$ x_2(t) = x_{2i} + v_{2}t + \frac{1}{2}a_2t^2 $$
 
Generally all the sub questions are about when the "proper" quadratic equation has none, one positive (and one negative) or two positive solutions (solutions for the time t when the collision happens). Remember , time can be only positive.
 
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It seems to me that you can answer the question quite easily and without equations if you consider the situation from the point of view of an observer sitting at rest on particle 1. He sees particle 2 having (relative) acceleration ##a_{rel}=a_2-a_1## and (relative) velocity ##v_{rel}=v_2-v_1##. There are four possibilities
  1. ##a_{rel} >0## and ##v_{rel} >0##
  2. ##a_{rel} >0## and ##v_{rel} <0##
  3. ##a_{rel} <0## and ##v_{rel} >0##
  4. ##a_{rel} <0## and ##v_{rel} <0##
For each of these possibilities, can you figure out the motion of particle 2 as seen by the observer on particle 1? The number of crashes will be the same as seen by this observer and an observer who sees both particles accelerate.
 
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Yigitu17 said:
Homework Statement:: Hello everyone, I have recently joined a physics summer school, for which I have to do homework every day. But I couldn't manage to solve today's problem, so I'm seeking help from you guys.

The question is about two particles moving on a one dimensional path. First one is at x=0 when t=0, and moves with a velocity of V1 and acceleration a1. The other one is at x=L>0 when t=0 and moves with a velocity of V2 and acceleration a2.
Relevant Equations:: x(t)=x0+v*t+1/2*a*t^2

couldn't eliminate t
It is not a matter of eliminating t. They crash if ##x_1(t)=x_2(t)## for some t. For what relationships between ##v_1, v_2, a_1, a_2, L## does such a t exist?
 

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